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Natasha2012 [34]
3 years ago
12

You pull a wagon carrying your younger brother 1000 meters (1 km) to the store using 20 newtons of force the whole way. It takes

you 15 minutes to get there. How much power did you generate, in joules per minute? In watts?
Physics
1 answer:
Veseljchak [2.6K]3 years ago
8 0

Lifting Weights: On earth it takes about 10 Newton-meters (N-m) of energy to raise a 1 kilogram mass to a height of 1 meter. Since 1 N-m equals 1 Joule, that's 10 Joules. If it takes 1 second to lift the weight 1 meter, than you have converted 10 Joules of energy to potential energy in one second.


Hope this helps!

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A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from zero to 9.41 m
Svetach [21]

Answer:

the impulse experienced by the passenger is 630.47 kg

Explanation:

Given;

initial velocity of the car, u = 0

final velocity of the car, v = 9.41 m/s

time of motion of the car, t = 4.24 s

mass of the passenger in the car, m = 67 kg

The impulse experienced by the passenger is calculated as;

J = ΔP = mv - mu = m(v - u)

           = 67(9.41 - 0)

           = 67 x 9.41

           = 630.47 kg

Therefore, the impulse experienced by the passenger is 630.47 kg

8 0
3 years ago
Which of the following is composed of only one kind of atom?
UNO [17]

Answer:

An element is a pure substance and is made of only one type of atom; it cannot be broken down into a simpler substance.

3 0
2 years ago
30 km/h is _________m/s?<br> A.)8.3<br> B.)5.6<br> C.)13.9<br> D.)11.1
Juli2301 [7.4K]

Answer:

Correct  Option :-  A

Explanation:

3 0
2 years ago
The parachute on a drag racing car deploys at the end of a run. If the car has a mass of 820 kg and the car is moving 36 m/s, wh
Lelechka [254]

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

v^2=v^2_o-2ax

where,

v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}

Next, consider that the formula for the force is:

F=ma

where,

m: mass of the car = 820 kg

a: deceleration of the car = 0.66m/s^2

Replace the previous values and simplify:

F=(820kg)(0.66\frac{m}{s^2})=542.20N

Hence, the required force to stop the car is 542.20N

4 0
1 year ago
An 18kg block moving at 6 m/s has kinetic energy of
sergey [27]

½ × 18 × 6² = 324 J

hope that helps^^

6 0
3 years ago
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