Answer:
10×2=20
10×2÷64=??
I am not sure what you are trying to say...
Explanation:
It is given that,
Diameter of loop, d = 1.4 cm
Radius of loop, r = 0.7 cm = 0.007 m
Magnetic field, 
(A) Magnetic field of a current loop is given by :

I is the current in the loop


I = 27.85 A
(B) Magnetic field at a distance r from a wire is given by :



r = 0.00222 m

Hence, this is the required solution.
Answer:
F = 1300 N
Explanation:
F = mv²/R = 0.4(100²)/3 = 1333.3333...
Answer:
31.905 ft/s²
Explanation:
Given that
Mass of the pilot, m = 120 lb
Weight of the pilot, w = 119 lbf
Acceleration due to gravity, g = 32.05 ft/s²
Local acceleration of gravity of found by using the relation
Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)
119 = 120 * a/32. 174
119 * 32.174 = 120a
a = 3828.706 / 120
a = 31.905 ft/s²
Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²