Answer:
I. Stopping acceleration = 6 m/s²
II. Stopping distance, S = 75 meters
Explanation:
Given the following data;
Final velocity = 30 m/s
Time = 5 seconds
To find the stopping acceleration;
Mathematically, acceleration is given by the equation;
Substituting into the equation;
Acceleration = 6 m/s²
II. To find the stopping distance, we would use the third equation of motion;
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
30² = 0² + 2*6*S
900 = 12S
S = 900/12
S = 75 meters
Answer:
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The answer is equal and opposite forces.
Answer:
1317.52 Newton
Explanation:
Mass of sensor = m = 129 kg
Acceleration of the sensor = a = 2.84 m/s²
g = Acceleration due to gravity = 9.81 m/s²
= Force on the laser sensor due to motion = 129×2.84 = 366.36 N
= Force due to gravity on the laser = mg = 129×9.81 = 1265.49 N
Tension in the cable
∴ The tension in the cable towing the sensor is 1317.52 Newton