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aivan3 [116]
3 years ago
8

Select a musical instrument. Research the instrument and explain how it works in terms of sound production and resonance. Descri

be how a musician can vary the pitch and loudness of the notes. Explain why different types of musical instruments sound different, even though they play the same notes.
Physics
2 answers:
iren [92.7K]3 years ago
7 0
1. I think a drum would be the easiest instrument to explain. You can vary the pitch and loudness by hitting it with different intensities or at different points or angles.

PS. I'm not talking about a drumset. I'm talking about an ordinary drum.

2. Different types of instruments sound different even though they play the same notes because they use different mechanisms for producing sound.

MrRa [10]3 years ago
3 0

Answer:

Explanation:

Xylophones is an instrument which has wooden bars attached to mallet.

When bars are hit, a sound is produced which resonate in the wooden boxes.

These wooden bars are of different sizes thus there pitch different from each other.

The longer the bars, more time the sound will be there hence lower will be the pitch.

As musical instruments are different in structure, they have different nature and produce different sounds.

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andreyandreev [35.5K]

Explanation:

Let \textbf{A} = 6\hat{\textbf{i}} + 4\hat{\textbf{j}} - 2\hat{\textbf{k}} and \textbf{B} = 2\hat{\textbf{i}} - 2\hat{\textbf{j}} + 3\hat{\textbf{k}}

The sum of the two vectors is

\textbf{A + B} = (6 + 2)\hat{\textbf{i}} + (4 - 2)\hat{\textbf{j}} + (-2 + 3)\hat{\textbf{k}}

= 8\hat{\textbf{i}} + 2\hat{\textbf{j}} + \hat{\textbf{k}}

The difference between the two vectors can be written as

\textbf{A - B} = (6 - 2)\hat{\textbf{i}} + (4 - (-2))\hat{\textbf{j}} + (-2 - 3)\hat{\textbf{k}}

= 4\hat{\textbf{i}} + 6\hat{\textbf{j}} - 5\hat{\textbf{k}}

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the pygmy shrew has an average mass of 2.0 g if 49 of these shrew are placed on a spring scale with a spring constant of 24 N/m
olga_2 [115]

Answer:

Spring's displacement, x = -0.04 meters.

Explanation:

Let the spring's displacement be x.

Given the following data;

Mass of each shrew, m = 2.0 g to kilograms = 2/1000 = 0.002 kg

Number of shrews, n = 49

Spring constant, k = 24 N/m

We know that acceleration due to gravity, g is equal to 9.8 m/s².

To find the spring's displacement;

At equilibrium position:

Fnet = Felastic + Fg = 0

But, Felastic = -kx

Total mass, Mt = nm

Fg = -Mt = -nmg

-kx -nmg = 0

Rearranging, we have;

kx = -nmg

Making x the subject of formula, we have;

x = \frac {-nmg}{k}

Substituting into the formula, we have;

x = \frac {-49*0.002*9.8}{24}

x = \frac {-0.9604}{24}

x = -0.04 m

Therefore, the spring's displacement is -0.04 meters.

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You add 500 mL of water at 10°C to 100 mL of water at 70°C. What is the
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Answer:

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