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4 years ago

Where does a rider on a roller coaster get energy?

Physics

2 answers:

Annette [7]4 years ago

5 0

Gravitational potential energy.

As the rider falls, the GPE is converted into kinetic energy.

liraira [26]4 years ago

5 0

He gets it from the huge motor that lifts the cars and people to the top of the first hill and then let's them go.

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A fillet weld has a cross-sectional area of 25.0 mm2and is 300 mm long. (a) What quantity of heat (in joules) is required to acc

HACTEHA [7]

Answer:

77362.56 J

163730.28571 J

Explanation:

A = Area = 25 mm²

l = Length = 300 mm

K = Constant = $3.33\times 10^{-6}$

$\eta$ = Heat transfer factor = 0.75

$f_m$ = Melting factor = 0.63

T = Melting point of low carbon steel = 1760 K

Volume of the fillet would be

$V=Al\\\Rightarrow V=25\times 300\\\Rightarrow V=7500\ mm^3=7500\times 10^{-9}\ m^3$

The unit energy for melting is given by

$U_m=KT^2\\\Rightarrow U_m=3.33\times 10^{-6}\times 1760^2\\\Rightarrow U_m=10.315008\ J/mm^3$

Heat would be

$Q=U_mV\\\Rightarrow Q=10.315008\times 7500\\\Rightarrow Q=77362.56\ J$

Heat required to weld is 77362.56 J

Amount of heat generation is given by

$Q_g=\dfrac{Q}{\eta f_m}\\\Rightarrow Q_g=\dfrac{77362.56}{0.75\times 0.63}\\\Rightarrow Q_g=163730.28571\ J$

The heat generated at the welding source is 163730.28571 J

7 0

4 years ago

A runner changing speed from 3 meters per second to 5 meters per second is an example of

Kay [80]

Answer:

Acceleration

Explanation:

Acceleration is the change in velocity/speed per unit time

3 0

3 years ago

An is a representation of something in the natural world .

garik1379 [7]

A Representation of something in the natural world is A Scientific Law

4 0

3 years ago

What are the properties of metal that make it a usful material for electricians

steposvetlana [31]

A property of a metal is that it has delocalised electrons, electrons that are mobile and free to move throught the structure, thus a metal can conduct electricity

8 0

3 years ago

A projectile is fired at t = 0 with an initial velocity ofvi at an angle of θ with respectto the horizontal towards the vertical

ivolga24 [154]

Answer:

$t=d/(v_{o}*cos(\alpha ))$

$y =d*tan(\alpha )- 1/2*g^{2}d^{2}/(v_{o}^{2}*(cos(\alpha ))^2)$

Explanation:

Kinematics equation in the axis X:

$x=v_{o}*cos(\alpha )*t$

The projectile strikes the building at time t:

$d=v_{o}*cos(\alpha )*t$

$t=d/(v_{o}*cos(\alpha ))$ (1)

Kinematics equation in the axis Y:

$y =v_{o}*sin(\alpha )*t - 1/2*gt^{2}$ (2)

We replace (1) in (2):

$y =v_{o}*sin(\alpha )*d/(v_{o}*cos(\alpha )) - 1/2*g(d/(v_{o}*cos(\alpha )))^{2}$

$y =d*tan(\alpha )- 1/2*g^{2}d^{2}/(v_{o}^{2}*(cos(\alpha ))^2)$ (2)

4 0

3 years ago