Question

Young David who slew Goliath experimented with slings beforetackling the giant. He found that he could revolve a sling oflength 0.600 m at the rate of9.00 rev/s. If he increased the lengthto 0.900 m, he could revolve the slingonly 7.00 times per second.(a) What is the speed of the stone for eachrate of rotation?1 m/s at 9.00 rev/s2 m/s at 7.00 rev/s(b) What is the centripetal acceleration of the stone at9.00 rev/s?3 m/s2(c) What is the centripetal acceleration at 7.00 rev/s?4 m/s2

Answer 1

Answer:

(a) velocity at 9 rev/s is 34.3m/s and the velocity at 7rev/s is 40.4 m/s. These were values can be gotten by using the formula v = 2(pi)R/T. Where T is the period. T = 1/w(angular velocity).

(b) acceleration at 9.0rev/s is 1961 m/s²

(c) acceleration at 7.0rev/s is 1814 m/s²

These values can be gotten by using the formula a = v²/R

Explanation:

The full solution can be found in the attachment below.

Thank you for reading.