The compound LiBr is an example of

A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa

Whitepunk [10]

Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

$Q=P\tan\phi$ ...(I)

We need to calculate the $\phi$

Using formula of $\phi$

$\phi=\cos^{-1}(Power\ factor)$

Put the value into the formula

$\phi=\cos^{-1}(0.6)$

$\phi=53.13^{\circ}$

Put the value of Φ in equation (I)

$Q=600\tan(53.13)$

$Q=799.99\ kVAR$

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

$Q'=600\tan(0.95)$

$Q'=9.94\ KVAR$

We need to calculate the difference between Q and Q'

$Q''=Q-Q'$

Put the value into the formula

$Q''=799.99-9.94$

$Q''=790.05\ KVAR$

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

8 0

3 years ago

A student attaches a 20 ohm resistor to a battery and measures a current of 0.30 A. What is the voltage of the battery?

Sati [7]

Answer:6v

Explanation:

Current=0.30A

Resistance=20ohms

voltage=current x resistance

Voltage=0.30 x 20

Voltage=6v

4 0

2 years ago

BEST ANSWER GETS MARKED AS BRAINLIEST!!!! Can someone PLZ help me come up with a study method, no matter what I try, I just can'

Leni [432]

For physics, I would recommend to just keep doing practice problems and reviewing notes. Repetition of the same concepts will help drill it into your brain. Hope that helps!

8 0

3 years ago

Read 2 more answers

Two long straight parallel wires are separated by 7.0cm. There is a 2.0A current flowing in the first wire. If the magnetic fiel

aliina [53]

Answer:

The current in the second wire is 4.4 A.

Explanation:

Given that,

Distance =7.0 cm

Current in first wire = 2.0 A

The magnetic field strength is zero at distance of 2.2 cm from the first wire.

We need to calculate the current in the second wire

Using formula of magnetic field

$B=B_{1}-B_{2}$

$0=\dfrac{\mu_{0}I_{1}}{2\pi r_{1}}-\dfrac{\mu_{0}I_{2}}{2\pi r_{2}}$

$\dfrac{\mu_{0}I_{1}}{2\pi r_{1}}=\dfrac{\mu_{0}I_{2}}{2\pi r_{2}}$

$\dfrac{I_{1}}{r_{1}}=\dfrac{I_{2}}{(d-r_{1})}$

Here, $r_{2}=d-r_{1}$

$I_{2}=\dfrac{I_{1}\times(d-r_{1})}{r_{1}}$

Put the value into the formula

$I_{2}=\dfrac{2.0\times(7.0-2.2)}{2.2}$

$I_{2}=4.4\ A$

Hence, The current in the second wire is 4.4 A.

4 0

2 years ago

Which equations represent the relationship between wavelength and frequency for a sounds wave

ioda

Waves can be described using a number of different characteristics of a wave. Wavelength and frequency are two such characteristics. The relationship between wavelength and frequency is that the frequency of a wave multiplied by its wavelength gives the speed of the wave

6 0

2 years ago