Answer:
The average atomic weight = 121.7598 amu
Explanation:
The average atomic weight of natural occurring antimony can be calculated as follows :
To calculate the average atomic mass the percentage abundance must be converted to decimal.
121 Sb has a percentage abundance of 57.21%, the decimal format will be
57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .
123 Sb has a percentage abundance of 42.79%, the decimal format will be
42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .
Next step is multiplying the fractional abundance to it masses
121 Sb = 0.5721 × 120.904 = 69.169178400
123 Sb = 0.4279 × 122.904 = 52.590621600
The final step is adding the value to get the average atomic weight.
69.169178400 + 52.590621600 = 121.7598 amu
❌formed by 2 ions
❌ionic bonds
✅yes because of solvation
✅yes electrolytes are substances that break apart into ions when dissolved
✅in itself but salt water is a good conductor
✅such as water
Answer:
C. +5
Explanation:
Oxygen is always -2. And the sum of the oxidation numbers must be equal to the charge. So:
2x + 7(-2) = -4
2x - 14 = -4
2x = 10
x=5
First you need to know how ionic compounds are created!
Ionic compounds are formed by IONS (Obviously, what am I, a dummy?)
There are two types of ions: anions and cations.
Anions can only be formed by nonmetals, and cations can only be formed by metals.
In order for ions to bond, there must be one anion and one cation, because opposite charges attract.
Let's look at your choices.
1) Ca + Br can form ionic bonds
2) Na + F can form ionic bonds
3) Li + Cl can form ionic bonds
However...
4) Mg + Ar
This is a special case. Ar is a NOBLE GAS, which means that it has the maximum number of valence electrons (8) in its outermost shell. Therefore, ANY type of bonding is IMPOSSIBLE.
Your answer should be 4) Mg + Ar
