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Natasha2012 [34]
3 years ago
12

2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g) When 2 moles of Na react with water at 25°C and 1 atm, the volume of H2 formed is 24.5 L. C

alculate the magnitude of work done in joules when 0.45 g of Na reacts with water under the same conditions. (The conversion factor is 1 L · atm = 101.3 J.)
Chemistry
1 answer:
olga nikolaevna [1]3 years ago
3 0

Answer:

Magnitude of work done = 24.28 J

Explanation:

No. of moles = Reacting mass/ Molar mass

Reacting mass of Na = 0.45 g

Molar mass of sodium = 23g/mol

∴ No. of moles of sodium = 0.45/23 = 0.0196 mole

If 2 moles of Na react with water at 25°C and 1 atm, 24.5 L of H₂ was formed.

∴ when 0.0196 mole of Na react with water under the same conditions, (24.5×0.0196)/2 L of H₂  will be formed.

⇒ (24.5×0.0196)/2 L = 0.24 L

0.24 L × 1 atm = 0.24 L . atm

Since  1 L · atm = 101.3 J

∴      0.24 L . atm = (0.24 L . atm ×101.3)/1 = 24.28 J

Magnitude of work done = 24.28 J

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weqwewe [10]

Answer:

Nitrogen (N), carbon (C), hydrogen (H) and oxygen (O).

Explanation:

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Given the shown organic compound, we refer to types of atoms to the elements present in the compound, thus, we find nitrogen (N), carbon (C), hydrogen (H) and oxygen (O) that are bonded via single or double bonds in such compound.

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4 0
3 years ago
Which type of van der walls force is responsible for holding polar molecules together? london dispersion dipole-dipole hydrogen
svet-max [94.6K]

Answer:

dipole-dipole

Explanation:

Polar molecules are formed as result of covalent bonds between atoms.

Dipole-dipole attraction are intermolecular bonds. Both London dispersion forces and dipole-dipole attraction are van der waals forces.

In dipole-dipole attraction, polar molecules (unsymmetrical molecules) line up such that the positive pole of one molecule attracts the negative pole of another. Example of such is found in HCl.

4 0
3 years ago
The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and
zavuch27 [327]

Answer:

The correct option is;

c. 0.167

Explanation:

The parameters given are;

The mean, μ = 13.9 Gigagrams/year

The standard deviation, σ = 5.8 Gigagrams/year

The z-score formula is given as follows;

z = \dfrac{x - \mu }{\sigma }

Where:

x = Observed score = 11.5 Gigagrams/year

We have;

z = \dfrac{11.5 - 13.9 }{5.8 } =  \dfrac{-2.4 }{5.8 } = 0.4138

From the z-score table relations/computation, the probability (p-value) = 0.6605

Where:

x = Observed score = 14 Gigagrams/year

We have;

z = \dfrac{14- 13.9 }{5.8 } =  \dfrac{0.1}{5.8 } = 0.01724

From the z-score table relations/computation, the probability (p-value) = 0.4931

Therefore, the probability, p_{ca}, that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 15.5 Gigagrams/year and 14 Gigagrams/year = The area under the normal curve bounded by the p-values for the two amounts of carbon emission

Which gives;

p_{ca} = 0.6605 - 0.4931 = 0.1674 ≈ 0.167

Therefore, the correct option is c. 0.167.

4 0
4 years ago
Calculate the silver ion concentration in a saturated solution of silver(I) sulfate (K sp = 1.4 × 10 –5). 1.5 × 10–2 M 1.4 × 10–
spin [16.1K]

Answer:

3.0x10⁻²M

Explanation:

Silver sulfate, Ag₂SO₄, has a product constant solubility equilbrium of:

Ag₂SO₄(s) ⇄ 2Ag⁺ + SO₄²⁻

When an excess of silver sulfate is added, some Ag₂SO₄ will react producing Ag⁺ and SO₄²⁻ until reach the equilbrium determined for the formula:

ksp = 1.4x10⁻⁵ = [Ag⁺]² [SO₄²⁻]

Assuming the Ag₂SO₄ that react until reach equilibrium is X, we can replace in Ksp expression:

1.4x10⁻⁵ = [Ag⁺]² [SO₄²⁻]

1.4x10⁻⁵ = [2X]² [X]

1.4x10⁻⁵ = 4X³

3.5x10⁻⁶ = X³

0.015 = X

As [Ag⁺] is 2X:

[Ag⁺] = 0.030 = 3.0x10⁻²M

The answer is:

<h3>3.0x10⁻²M</h3>
7 0
3 years ago
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Anastaziya [24]
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3 0
3 years ago
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