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3 years ago

If a golf ball and a bowling ball are rolling at the same speed, the _________ ball has a greater momentum.

Physics

2 answers:

koban [17]3 years ago

8 0

Answer: Bowling ball has a greater momentum than a golf ball.

Explanation:

Momentum is defined as the product of mass and velocity of an object. Mathematically,

$p=mv$

where,

p = momentum of the object

m = mass of the object

v = velocity of an object

Momentum is directly dependent on mass and velocity of the object.

We are given that both the balls are moving with the same speed which means that the velocity of both the balls are same. So, the momentum will be dependent on mass of the ball only.

The ball having greater mass will have higher momentum than the ball having less mass.

As, mass of bowling ball is very high than the mass of the golf ball. Thus, it will have greater momentum.

Elis [28]3 years ago

6 0

If a golf ball and Bowling ball are rolling at the same speed, the bowling ball would have greater momentum.

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Describe the kinetic molecular theory

tatuchka [14]

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3 years ago

A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with

Ray Of Light [21]

Answer:

See below

Explanation:

Vertical position = 45 + 20 sin (30) t - 4.9 t^2

when it hits ground this = 0

0 = -4.9t^2 + 20 sin (30 ) t + 45

0 = -4.9t^2 + 10 t +45 = 0 solve for t =4.22 sec

max height is at t= - b/2a = 10/9.8 =1.02

use this value of 't' in the equation to calculate max height = 50.1 m

it has 4.22 - 1.02 to free fall = 3.2 seconds free fall

v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL

it will also still have horizontal velocity = 20 cos 30 = 17.32 m/s

total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s

Horizontal range = 20 cos 30 * t = 20 * cos 30 * 4.22 = 73.1 m

8 0

2 years ago

Please help me

Grace [21]

Answer:

a. 60 N*s

b. 60 (kg*m)/s

c. 3 m/s

Explanation:

Givens:

m = 20 kg

v_i = 0 m/s

t = 10 s

F = 6 N

a) Impulse:

I = F*t

I = 6 N*10 s

I = 60 N*s

b) Momentum:

p = v*m

F = m(a)

a = F/m

a = 6 N/20 kg

a = 0.3m/s^2

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

p = 3 m/s*20 kg

p = 60 (kg*m)/s

c. Final velocity

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

6 0

3 years ago

At what angle of projectile range of maximum

Agata [3.3K]

Answer:

$45°$

Explanation:

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

7 0

3 years ago

Explain the terms boiling and boiling point.

Volgvan

The particular temperature at which vaporisation occurs is known as the boiling point of liquid. Volume of water increases when it boils at 100° C. 1 cm3 of water at 100 ° C becomes 1760 cm3 of steam at 100 ° C.

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3 0

3 years ago