Two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. One of t
he blocks, with a mass of 1.0 kg accelerates downward at 34g. What is the mass of the other box?
1 answer:
Answer:
<h2>1/7 kg</h2>Explanation:
Find the diagram attached for better understanding of the question.
Given the mass of one of the blocks to be 1.0kg and accelerates downward at 3/4g.
g = acceleration due to gravity.
Let the block accelerating downward be M, mass of the other body be 'm' and the acceleration of the body M be 'a'.
M = 1.0 kg and a = 3.4g
According to newton's second law;
For body of mass m;
T - mg = ma ... (1)
For body of mass M;
Mg - T = Ma ... (2)
Adding equation 1 ad 2;
+Mg -mg = ma + Ma
Ma-Mg = -mg-ma
M(a-g) = -m(a+g)
Substituting M = 1.0 kg and a = 3/4g into the resulting equation;
3/4 g-g = -m(3/4 g+g)
3/4 g-g = -m(7/4 g)
-g/4 = -m(7/4 g)
1/4 = 7m/4
28m = 4
m = 1/7 kg
Therefore the mass of the other box is 1/7 kg
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Answer:
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
Q = Heat absorbed= Joules
m= mass of copper = 454 g
c = specific heat capacity =
Initial temperature of the copper = = 23.0°C
Final temperature of the water = = ?
Change in temperature ,
Putting in the values, we get:
The final temperature of copper will be
The kinetic energy of the cart is 24 J.
<u>Explanation:</u>
The acceleration of a given mass from rest to the velocity is known as kinetic energy. It gains energy from acceleration and remains in this state until the speed of the object changes.
The kinetic energy is the given by,
K.E = 1/2 mv^2
Given the mass m = 3 kg, v = 4 m / s.
K.E = 1/2 3
(4)^2
K.E = 24 J.