I don't know what model you're referring to so I can't answer the question. However, upon researching, I found a similar problem. I posted it as an attached picture. Looking at the model, the amount of grams a herbivore eat each day corresponds to the arrow pointing inwards. Since the label says 4.0 g,
<em>the answer is 4 g per day</em>.
Answer:
- <u><em>You should expect that the ionic bond in LiBr is stronger than the bond in KBr.</em></u>
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Explanation:
The<em> ionic bonds</em> are formed by the electrostatic attraction between the ions, cations and anions.
In KBr the cation is K⁺ and the anion is Br⁻.
In LiBr the cation is Li⁺ and the anion is Br⁻.
You must expect that the bond strength depends mainly on the charges present on each ion and the distance between them.
Nevertheless, the effect of the distance between the radius dominate the trendency of the bond strength, which makes that the ionic strength trend be related to the ionic radius trend.
Lithium is a smaller ion than Potassium (both are in the same group and Lithium is above Potassium).
Thus, you should expect that the Li ion is closer to the Br ion than what the K ion is to the Br ion and expect that the bond between a Li ion and the Br ion be stronger than the bond between the K ion and the Br ion.
Answer:
Hydrocarbon combustion refers to the chemical reaction where a hydrocarbon reacts with oxygen to create carbon dioxide, water, and heat. Hydrocarbons are molecules consisting of both hydrogen and carbon. ... Methane combining with 2 oxygen to form carbon dioxide, water and heat.
have<span> 6 electrons. i hope this answer helps
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Answer:
0.542M HCl
Explanation:
The reaction of H₂SO₄ with NaOH is:
H₂SO₄ + 2 NaOH → 2H₂O + Na₂SO₄
<em>Where 1 mole of acid reacts with 2 moles of NaOH</em>
Moles of H₂SO₄ are:
0.0500L × (0.361mol / L) = 0.01805 moles H₂SO₄
Thus, moles of NaOH that neutralize this acid are:
0.01805 moles H₂SO₄ × (2 mol NaOH / 1 mol H₂SO₄) = 0.0361 moles NaOH
And concentration is:
0.0361 moles NaOH / 0.0200L = <em>1.805M</em>
And, reaction of NaOH with HCl is:
NaOH + HCl → H₂O + NaCl
<em>Where 1 mole of NaOH reacts per mole of NaOH</em>
As you use 30.0mL = 0.0300L of NaOH to neutralize the HCl acid, moles of acid are:
0.0300L × (1.805mol / L) = 0.05415 moles NaOH = moles HCl
In 0.1000L:
0.05415 moles HCl / 0.1000L = <em>0.542M HCl</em>
