Given :
A wrecking ball of mass 500 kg hangs form a crane by a cable of length 25 m
this wrecking ball is released from an angle of 40 degrees.
To Find :
The height from the lowest point of the arc.
Solution :
From the attached image we have to find the value of h.
So,
Hence, this is the required solution.
Answer:
2361 Newtons
Explanation:
From the second Newton's law of motion;
F = ma
In this case;
we are given;
Mass as 9.5 g
Initial speed as 0 m/s
Final velocity as 650 m/s
Distance is 0.85 m
Using the equation;
V² = U² + 2as
But u = 0
v² = 2as
Therefore;
a = v² ÷ 2s
= 650² ÷ 2(0.85)
= 248,529.40 m/s²
But;
F = ma
= 0.0095 kg × 248,529.40 m/s²
= 2361 Newtons
Therefore;
The average net force required to accelerate the bullet is 2361 Newtons.
Answer:
As you move across a period, the atomic mass increases because the atomic number also increases
Explanation:
When the atomic number increases, this means that there are more protons and neutrons that add to the atomic mass of an atom.
