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3 years ago

What are pollutants of greatest concern and who is at risk?

1 answer:

6 0

Oil leakage in aquatic areas. (fish)
Burning fuel. (Air/global warming)
Toxic waste burried in dirt (living Creatures)
Lights/Electricity (destroyes Birds migration)
Noise (migration on dolphines and other sea mammals)

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Your friend asks you to describe pseudoscience. You reply pseudoscience is

oksian1 [2.3K]

The answer is most likely D. hope that helped

5 0

3 years ago

Read 2 more answers

a car travelling 90 km/hr is 100m behind a truck travelling 75 km/hr. Assuming both vehicles moving at constant velocity,calcula

nika2105 [10]

90t - .100 = 75t

90t - 75t = 0.100

15t = 0.100

t = 0.0067

t = 0.0067 hours or 24.12 seconds (.0067 * 60 minutes * 60 seconds)

7 0

3 years ago

What is the magnetic force on a proton that is moving at 4.5 107 m/s to the right through a magnetic field that is 1.6 T and poi

pickupchik [31]

The answer is letter C. 1.2 10^-11 N up
Solution:
F= Bqvsin(theta)
theta = sin 90 = 1
F= 1.4 T * 1.6x10^-19 * 5.2x10^7 ms^-1
F= 1.16 x 10^-11 N
Then the direction is upward.

6 0

3 years ago

Read 2 more answers

Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road oriented at an angle of 25

rjkz [21]

Answer:

8.6 miles

Explanation:

In order to calculate the straight-line distance between the starting point and the ending point, we need to resolve each part of the displacement into two perpendicular directions, let's say horizontal (x) and vertical (y) directions.

In the first part, Erica moves for 5.2 miles 25∘ north of east. Resolving into the two directions:

$d_{1x} = 5.2 cos 25^{\circ}=4.7 mi\\d_{1y} = 5.2 sin 25^{\circ} =2.2 mi$

In the second part, Erica moves 5.0 miles north, so the components are

$d_{2x} = 0\\d_{2y} = 5.0 mi$

So the components of the net displacement are

$d_x = d_{1x}+d_{2x}=4.7+0 = 4.7 mi\\d_y = d_{1y}+d_{2y} =2.2+5.0 = 7.2 mi$

And the magnitude of the net displacement is

$d=\sqrt{d_x^2 +d_y^2}=\sqrt{4.7^2+7.2^2}=8.6 mi$

8 0

3 years ago

A 2.4-m high 200-m2 house is maintained at 22Â°C by an air-conditioning system whose COP, is 3.2. It is estimated that the kitch

kotegsom [21]

Answer:

The amount that is "vented" out by "the fans" is $0.50 for 10 hours.

Option: a

Explanation:

"Energy discharged by air in every hour" can be determined by,

$\mathrm{Q}=\mathrm{m}_{\mathrm{air}} \mathrm{C}_{\mathrm{p}} \Delta \mathrm{T}$

Q = heat energy (Joules, J)

m = mass of a substance (kg)

c = specific heat (units J/kg∙K)

$\mathrm{m}_{\mathrm{air}}=\rho \mathrm{v}$

$\text { Density of air } \rho=1.20 \mathrm{kg} / \mathrm{m}^{3}$

$\text { Density of air } \rho=1.20 \times 200 \times 2.4$

$\text { Density of air } \rho=576 \mathrm{kg}$

∆T = 10 hours

$\text { Specific Heat Capacities of Air. The nominal values used for air at } 300 \mathrm{K} \text { are } \mathrm{C_P}=1.00 \mathrm{kJ} / \mathrm{kg} . \mathrm{K}$