Alkynes can be reduced to<span> trans</span>-alkenes using Li(lithium) in NH₃(ammonia).
<span>Lithium is a reducing agent.
In this case product is trans-2-butene.
Reaction:
CH</span>₃<span>-C≡C-CH</span>₃ (2-butyne)<span> + 2 Li in N<span>H</span></span>₃<span> (liq) ——>
trans CH</span>₃<span>-CH=CH-CH</span>₃<span> + 2 LiN<span>H</span></span>₂ (lithium-amide).<span><span><span>
</span></span></span>
Answer:
26.9%
Explanation:
To obtain the percentage by mass of solution, do the following:
Data obtained from the question include:
Mass of HCl (solute) = 36g
Mass of water (solvent) = 98g
Mass of the solution = Mass of solute + Mass of solvent
Mass of the solution = 36 + 98 = 134g
Percentage by mass of the solution = Mass of solute/mass of solution x 100
Percentage by mass of solution = 36/134 x 100 = 26.9%
If a 3.50g sample of the hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate, the mass percent of water in the hydrate is 40%.
<h3>How to calculate mass percent?</h3>
The mass percent of hydrate in a sample can be calculated by dividing the mass of water in the sample by the mass of the hydrated compound.
According to this question, 3.50g sample of an hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate. The mass percent of water is calculated as follows:
Mass percent of water = (3.5-2.1)/3.5 × 100
Mass percent of water = 40%
Therefore, if a 3.50g sample of the hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate, the mass percent of water in the hydrate is 40%.
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Answer: Hydrocarbon fuels like methane (CH4) burn in the presence of oxygen to produce carbon dioxide and water. This process of combustion releases energy. When energy is released during the course of a chemical reaction, it is said to be an EXOTHERMIC reaction.
Explanation: