Suppose a blood vessel's radius is decreased to 87% of its original value by plaque deposits and the body compensates by increas
ing the pressure difference along the vessel to keep the flow rate constant.
By what factor must the pressure difference increase?
By what factor must the pressure difference increase?
1 answer:
Answer:
The pressure difference will increase by the factor of 1.75
Explanation:
For constant flow rate, coefficient of viscosity, length of the vessel and the pressure difference is inversely proportional to the fourth power of the radius of the blood vessel
Apply the principle of Poiseuille’s law.
Q = (P2 - P1)/R
Pls check the attached file for step by step solution of the question. It is submitted in this way as typing the equation may not be explanatory.
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Answer:
15.8 V
Explanation:
The relationship between capacitance and potential difference across a capacitor is:
where
q is the charge stored on the capacitor
C is the capacitance
V is the potential difference
Here we call C and V the initial capacitance and potential difference across the capacitor, so that the initial charge stored is q.
Later, a dielectric material is inserted between the two plates, so the capacitance changes according to
where k is the dielectric constant of the material. As a result, the potential difference will change (V'). Since the charge stored by the capacitor remains constant,
So we can combine the two equations:
and since we have
V = 71.0 V
k = 4.50
We find the new potential difference: