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Arisa [49]
4 years ago
14

One-dimensional, steady-state conduction with uniform internal energy generation occurs in a plane wall with a thickness of 50 m

m and a constant thermal conductivity of 5 W/mK . For these conditions, the temperature distribution has the form T(x)= a + bx + cx2. The surface at
x =0 has a temperature of T(0) = To = 120C and experiences
convection with a fluid for which T =20C and h= 500 W/m2 *K. The surface at x =L is well insulated.

(a) Applying an overall energy balance to the wall, calculate
the volumetric energy generation rate.

b) Determine the coefficients a, b, and c by applying

the boundary conditions to the prescribed temperature
distribution. Use the results to calculate and
plot the temperature distribution.
(c) Consider conditions for which the convection coefficient
is halved, but the volumetric energy generation
rate remains unchanged. Determine the new
values of a, b, and c, and use the results to plot the
temperature distribution. Hint: recognize that T(0)
is no longer 120C.
(d) Under conditions for which the volumetric energy
generation rate is doubled, and the convection coefficient
remains unchanged (h =500 W/m2 K),
determine the new values of a, b, and c and plot the
corresponding temperature distribution. Referring
to the results of parts (b), (c), and (d) as Cases 1, 2,
and 3, respectively, compare the temperature distributions
for the three cases and discuss the effects of
h and on the distributions.

Engineering
1 answer:
REY [17]4 years ago
3 0

Answer:

answers in the attachment

Explanation:

The detailed steps an appropriate derivation is shown in the attachment.

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A meter stick can be read to the nearest millimeter and a travelling microscope can be read to the nearest 0.1 mm. Suppose you w
german

Answer: No

Explanation:

Length= 2cm= 20mm

Now meter stick can read to nearest millimeter.

It is given that length is to be measured with a precision of 1% of 20mm= 1/100 * 20= 0.2mm

Since the least count is 1mm of meter stick and precision required is less than that. So, meter stick cannot be used for this, travelling microscope can be used for this as it can read to 0.1mm.

3 0
3 years ago
Two engineers are to solve an actual heat transfer problem in a manufacturing facility. Engineer A makes the necessary simplifyi
deff fn [24]

Answer:

Engineer A results will be more accurate

Explanation:

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Sedbober [7]
Get the app socratic I saw the answer to your question on the app but I ran out of screen time to show you
6 0
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Lorico [155]

Answer:

Apartment outlet 4pcs

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6 0
3 years ago
A fluid of density 900 kg/m3 passes through a converging section of an upstream diameter of 50 mm and a downstream diameter of 2
NISA [10]

Answer:

Q= 4.6 × 10⁻³ m³/s

actual velocity will be equal to 8.39 m/s

Explanation:

density of fluid = 900 kg/m³

d₁ = 0.025 m

d₂ = 0.05 m

Δ P = -40 k N/m²

C v = 0.89

using energy equation

\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g} = \dfrac{P_2}{\gamma}+\dfrac{v_2^2}{2g}\\\dfrac{P_1-P_2}{\gamma}=\dfrac{v_2^2-v_1^2}{2g}\\\dfrac{-40\times 10^3\times 2}{900}=v_2^2-v_1^2

under ideal condition v₁² = 0

v₂² = 88.88

v₂ = 9.43 m/s

hence discharge at downstream will be

Q = Av

Q = \dfrac{\pi}{4}d_1^2 \times v

Q = \dfrac{\pi}{4}0.025^2 \times 9.43

Q= 4.6 × 10⁻³ m³/s

we know that

C_v =\dfrac{actual\ velocity}{theoretical\ velocity }\\0.89 =\dfrac{actual\ velocity}{9.43}\\actual\ velocity = 8.39m/s

hence , actual velocity will be equal to 8.39 m/s

6 0
3 years ago
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