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Dafna11 [192]
3 years ago
10

Tech a says that the weight of the flywheel smoothest out the engines power pulses. Tech B says that the flexplate and torque co

nverter perform this same function. Who is correct?
Engineering
1 answer:
lakkis [162]3 years ago
4 0

Answer:

both statement is correct

Explanation:

Flywheel engine uses to reduce fluctuations.

And                                                                

FlexPlate is a metal disk that connects the output from the engine to the input of the torque converter. This will replace the flywheel

so that both statement is correct

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A piston moves a 25kg hammerhead vertically down 1m from rest to a
UkoKoshka [18]

Answer:

Total change in energy = 31 KJ.

Explanation:

Mass m=25 kg

Height h = 1 m

Initial velocity = 0

Final velocity = 50 m/s

Energy at initial condition

E_1=mgh+\dfrac{1}{2}mv^2

E_1=25\times 10\times 1+0

E_1=250\ J

Energy at final condition

E_2=0+\dfrac{1}{2}\times 25\times 50^2

E_2=31250\ J

So the change in energy = 31250 -250 J

The total change in energy = 31000 J

5 0
4 years ago
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A three-point bending test is performed on a glass specimen having a rectangular cross section of height d = 5.4 mm (0.21 in.) a
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5.21e-2mm

Explanation:

Please see attachment

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3 years ago
Un vendedor de camiones quiere suspender un vehículo de 4000 kg como se muestra en la figura, con fines publicitarios. La distan
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3 years ago
Can anyone solve this for me?sequential circuit ,flipflop
andrezito [222]

Explanation:

We assume the T flip-flop changes state on the rising edge of the clock input.

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6 0
2 years ago
A piston–cylinder device contains 0.78 kg of nitrogen gas at 140 kPa and 37°C. The gas is now compressed slowly in a polytropic
DiKsa [7]

Answer:

The entropy change of nitrogen during this process. is - 0.32628 kJ/K.

Explanation:

Solution

Given that:

A piston cylinder device contains =0.78 kg of nitrogen gas

Temperature = 37°C

The  nitrogen gas constant of R = 0.2968 kJ/kg.K

At room temperature cv = 0.743 kJ/kg.K

Now,

We assume that at specific condition the nitrogen can be treated as an ideal gas

Nitrogen has a constant volume specific heat at room temperature.

Thus,

From the polytropic relation, we have the following below:

T₂/T₁ =(V₁/V₂)^ n-1 which is,

T₂ = T₁ ((V₁/V₂)^ n-1

= (310 K) (2)^1.3-1 = 381.7 K

So,

The entropy change of nitrogen is computed as follows:

ΔSN₂ = m (cv₁ avg ln T₂/T₁ + ln V₂/V₁)

= (0.78) ((0.743 kJ/kg .K) ln 381.7 K/310K + (0.2968 kJ/kg. K) ln (0.5))

= 0.57954 * 0.2080 +  (-0.2057)

= 0.12058 + (-0.2057) = -0.32628

Therefore the entropy change of nitrogen during this process. is - 0.32628 kJ/K.

6 0
3 years ago
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