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Dafna11 [192]
3 years ago
10

Tech a says that the weight of the flywheel smoothest out the engines power pulses. Tech B says that the flexplate and torque co

nverter perform this same function. Who is correct?
Engineering
1 answer:
lakkis [162]3 years ago
4 0

Answer:

both statement is correct

Explanation:

Flywheel engine uses to reduce fluctuations.

And                                                                

FlexPlate is a metal disk that connects the output from the engine to the input of the torque converter. This will replace the flywheel

so that both statement is correct

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Of the cost reduction strategies for workers' compensation mentioned in the required readings, which one do you think would work
Vesnalui [34]

In industries together with production, we want people to address the manufacturing of merchandise and the usage of heavy machinery.

<h3>What is the painting situation?</h3>

In such painting situations, people are at risk of injuries, and this prices the maximum for the company. So so that you can put into effect value discount is such conditions we want to have right coincidence cowl plans for the people and make sure all of the protection precautions are taken withinside the factory.

  1. The people have to be properly educated on using protection measures and in case any injuries arise we have to have coverage claims in order that we not want to make investments extra cash and we also can offer protection and protection to the people.
  2. This approach is excellent for this enterprise due to the fact regardless of what number of precautions we take people are uncovered to fitness risks and as a result having the right coverage insurance is a superb value discount strategy.

Read more bout the compensation :

brainly.com/question/25273589

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3 0
2 years ago
15
AveGali [126]

Answer:

b

Explanation:

4 0
3 years ago
The longest_word function is used to compare 3 words. It should return the word with the most number of characters (and the firs
NARA [144]

Answer:

len(word2) >= len(word1) and len(word2) >= len(word3):

Question with blank is below

def longest_word(word1,word2,word3):

   if len(word1) >= len(word2) and len(word1) >= len(word3):

       word = word1

   elif _________________________________________

       word = word2

   else:

       word = word3

   return word

print(longest_word("chair","couch","table"))

print(longest_word("bed","bath","beyond"))

print(longest_word("laptop","notebook","desktop"))

print(longest_word("hi","cat","Cow"))

Explanation

In line 1 of the code word1, word2, and word3 are the parameters used to for the defining the longest_word function. They will be replaced by 3 words to be compared. The code that is filled in the blank is len(word2) >= len(word1) and len(word2) >= len(word3): It is a conditional statement that is true only if the number of characters in the string of word2 is greater than or equal to word1 and word2 is greater than that of word3 .

4 0
4 years ago
When they say in the United States that a car’s tire is filled “to 32 lb,”​ they mean that <br>its internal pressure is 32 lbf/i
arsen [322]

Answer:

0.71 lbf

Explanation:

Use ideal gas law:

PV = nRT

where P is absolute pressure,

V is volume,

n is number of moles,

R is universal gas constant,

and T is absolute temperature.

The absolute pressure is the sum of the atmospheric pressure and the gauge pressure.

P = 32 lbf/in² + 14.7 lbf/in²

P = 46.7 lbf/in²

Absolute temperature is in Kelvin or Rankine:

T = 75 + 459.67 R

T = 534.67 R

Given V = 3.0 ft³, and R = 10.731 ft³ psi / R / lb-mol:

PV = nRT

(46.7 lbf/in²) (3.0 ft³) = n (10.731 ft³ psi / R / lb-mol) (534.67 R)

n = 0.02442 lb-mol

The molar mass of air is 29 lbm/lb-mol, so the mass is:

m = (0.02442 lb-mol) (29 lbm/lb-mol)

m = 0.708 lbm

The weight of 1 lbm is lbf.

W = 0.708 lbf

Rounded to two significant figures, the weight of the air is 0.71 lbf.

3 0
3 years ago
Technicians have to determine the flow rate of water in a pipe with the aid of a venturi installation and a mercury au.oaeter. T
Schach [20]

Answer:

Manometric difference x=142.85 mm.

Explanation:

Given :

 Pipe diameter d_1=40 mm

venturi meter d_2=20 mm

We can know that discharge through venturi meter is given as

Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt {A_1^2-A_2^2}}

A_1=1.24\times 10^{-3},A_2=3.12\times 10^{-4}

Q=A_1V_1

Q=1.24\times 10^{-3}\times 1.5=0.00186 m^3/s

0.00186=0.97\dfrac{1.24\times 10^{-3}\times 3.12\times 10^{-4} \sqrt{2gh}}{\sqrt {(1.24\times 10^{-3})^2-(3.12\times 10^{-4})^2}}

h=1.8 m

We know that h=x\left (\dfrac{\rho_{hg}}{\rho_w}-1\right )

Where x is the manometric deflection

⇒ 1.8=x\left (\dfrac{13600}{1000}-1\right )

So x=14.28 mm

Manometric difference x=142.85 mm.

7 0
3 years ago
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