3 is correct because the .1 moles of the NO3 will be better option to decrease the solubility of the Silver Nitrate.
Answer:
5.37 × 10⁻⁴ mol/L
Explanation:
<em>A chemist makes 660. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a 0.00154 mol/L stock solution of magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.</em>
Step 1: Given data
- Initial concentration (C₁): 0.00154 mol/L
- Initial volume (V₁): 230. mL
- Final concentration (C₂): ?
- Final volume (V₂): 660. mL
Step 2: Calculate the concentration of the final solution
We want to prepare a dilute solution from a concentrated one. We can calculate the concentration of the final solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁ / V₂
C₂ = 0.00154 mol/L × 230. mL / 660. mL = 5.37 × 10⁻⁴ mol/L
The law of conservation of mass<span> states that </span>mass<span> in an isolated system is neither created nor destroyed by chemical reactions or physical transformations.
</span>
Answer:
4.75 moles of Fe
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
FeO + CO —> Fe + CO2
Now, we can determine the number of mole of iron, Fe produced by the reaction of 4.75 mol of FeO with excess CO as follow:
From the balanced equation above,
1 mole of FeO reacted to produce 1 mole of Fe.
Therefore, 4.75 moles of FeO will also react to produce 4.75 moles of Fe.
Therefore, 4.75 moles of Fe is produced.
