The average acceleration of the car in this process is -2 m/s²
<h3>
What is Acceleration ?</h3>
Acceleration can be defined as change in velocity per time taken. It is a vector quantity. That is, it has both the magnitude and direction. It is measured in m/s²
Given that a velocity of a car decreases from 28m/s to 20m/s in a time of 4 seconds. Then,
- Initial velocity u = 28 m/s
- Final velocity v = 20 m/s
From the definition of acceleration,
a = Δv / t
a = ( 20 - 28 ) / 4
a = -8 / 4
a = - 2 m/s²
Therefore, the average acceleration of the car in this process is -2 m/s² which mean that the car is decelerating.
Learn more about Deceleration here: brainly.com/question/25311290
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Answer:
The horizontal component of the vector ≈ -16.06
The vertical component of the vector ≈ 19.15
Explanation:
The magnitude of the vector,
= 25 units
The direction of the vector, θ = 130°
Therefore, we have;
The horizontal component of the vector, Rₓ =
× cos(θ)
∴ Rₓ = 25 × cos(130°) ≈ -16.06
<em>The horizontal component of the vector, Rₓ ≈ -16.06</em>
The vertical component of the vector, R
=
× sin(θ)
∴ R
= 25 × sin(130°) ≈ 19.15
<em>The vertical component of the vector, R</em>
<em> ≈ 19.15</em>
(The vector, R = Rₓ + R
= Rₓ·i + R
·j
∴
≈ -16.07·i + 19.15j)
Answer:
Anthracite coal contains the highest carbon content.
displacement --> it has a magnitude and a direction. Example 30m E of the starting point