Answer:
= 5.74W
=0.27 W
Explanation:
d= 2.6cm =>0.026m (for both the ceramic and the carpet )
Thermal conductivity of wool '
'= 
= 
= 0.04J/(sm °C)
Thermal conducticity of carpet '
' = 0.84 J/(sm °C)
Area 'A'= 
= 
= 77.2cm²=> 77.2 x 
m²
=33.0°C
=10.0°C
Average Power 
is determined by dividing amount of energy'Q' by time taken for the transfer't':
= Q/Δt
Due to conductivity, heat of flow rate will be P= dQ/dt
P=
= ![\frac{kA[T_{h}-T_{c} ]}{d}](https://tex.z-dn.net/?f=%5Cfrac%7BkA%5BT_%7Bh%7D-T_%7Bc%7D%20%5D%7D%7Bd%7D)
For CERAMIC:
=![\frac{k_{c} A[T_{h}-T_{c} ]}{d}](https://tex.z-dn.net/?f=%5Cfrac%7Bk_%7Bc%7D%20A%5BT_%7Bh%7D-T_%7Bc%7D%20%5D%7D%7Bd%7D)
=> [0.84 x 77.2 x (33-10) ]/0.026
= 5.74W
For WOOL CARPET:
= ![\frac{k_{w} A[T_{h}-T_{c} ]}{d}](https://tex.z-dn.net/?f=%5Cfrac%7Bk_%7Bw%7D%20A%5BT_%7Bh%7D-T_%7Bc%7D%20%5D%7D%7Bd%7D)
=> [0.04 x 77.2 x (33-10) ]/0.026
=0.27 W
Answer:
At 23.5 deg north of the equator this person would see the sun directly overhead at the summer solstice at noon
Number 3 I think there was so much going In ckcoc v K o n&+\
Work done is equal to the force applied multiplied by the distance moved in the direction of the force. The weight force acts vertically downwards and the distance moved is vertically upwards so they are in the same line. Hence W = Fx = 1250 * 2 = 2500J.
Power is the rate of work done, i.e. work done divided by time. P = W/t = 2500/3 = 833W (3sf)
Answer:
D The total energy in a closed system is a conserved quantity.
Explanation:
As we know by first law of thermodynamics that heat given to the system is equal to the Sum of change in internal energy of the system and Work done by the system
So we have
so we can say that heat given to the system is the form of energy which is converted into other forms and this total energy is conserved
So correct answer will be
D The total energy in a closed system is a conserved quantity.
