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Ratling [72]
3 years ago
7

A 30.0 kg object rests on a flat, frictionless surface. A rope lifts up on the object with a force of 309 N. What is the acceler

ation of the object?
Physics
1 answer:
saveliy_v [14]3 years ago
4 0
Total force = Frope - mg = 309-300
total force = ma
9 = 30a
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HELP
Free_Kalibri [48]

Answer:

Explanation:

Although there is absolutely NO regard for significant digits, I can help you with this, nonetheless.

The equation for Potential Energy is PE = mgh. We have everything but the height of the ball. We have to solve for that using a one-dimensional motion equation:

v² = v₀² + 2aΔx, where Δx is our displacement (the height we need for PE). Filling in and keeping in mind that at the max height of parabolic travel, the final velocity of the object is 0:

0 = (21.5)² + 2(-9.8)Δx and

0 = 462.25 - 19.6Δx and

-462.25 = -19.6Δx so

Δx = 23.58 m. Using this as the h in our PE equation:

PE = .19(9.8)(23.58) so

PE = 43.9 J, choice C.

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2 years ago
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Eddi Din [679]

Answer:

there are many types of family but main is 2

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1). joint family 2). nucleic family joint family has mother father grandfather grandmother uncle aunty children. and nucliec family has mother father and childrens

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3 years ago
Read 2 more answers
What affect does a tripling of the net force have upon the acceleration of the object ? Be quantitative
vovikov84 [41]
The formula of net Force is:
F = ma
where m is the mass of the object
a is the acceleration of the object

so if we triple the net force applied to the object:
3F = ma
a = 3F / m

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5 0
3 years ago
A charging RC circuit controls the intermittent windshield wipers in a car. The emf is 12.0 V. The wipers are triggered when the
lilavasa [31]

Answer:

R=803k\Omega

Explanation:

We have the following information,

V_0 = 12V\\V=10V\\c= 1.25*10^{-6}F\\t=1.8s

We apply the equation for capacitor charging the voltage across it,

V=V_0 (1-e^{-t/x})\\e^{-t/x}=1-(\frac{V}{V_0})\\-\frac{t}{Rc}=ln(\frac{V}{V_0})\\R=-\frac{t}{ln(\frac{V}{V_0})*c}

Replacing values,

R=-\frac{1.8}{ln(10/12)*1.25*10^{-6}}

R=803k\Omega

3 0
3 years ago
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