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Natali5045456 [20]
3 years ago
6

ANSWER ASAP PLZZZZ!!!!!!!!

Physics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer: your correct answer is a i took the test

Please i need brainlist i need one more and i level up :)

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If the distance between two charges is doubled, by what factor is the magnitude of the electric force changed? F_e final/F_e, in
motikmotik

To solve this problem we will apply the concepts related to Coulomb's law for which the Electrostatic Force is defined as,

F_{initial} = \frac{kq_1q_2}{r^2}

Here,

k = Coulomb's constant

q_{1,2} = Charge at each object

r = Distance between them

As the distance is doubled so,

F_{final} = \frac{kq_1q_2}{( 2r )^2}

F_{final} = \frac{ kq_1q_2}{ 4r^2}

F_{final} = \frac{1}{4} \frac{ kq_1q_2}{r^2}

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2 years ago
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