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Makovka662 [10]
3 years ago
11

What is the weight, on Earth, of a book with a mass of 16 kg? 16N 65N 113N 147N

Chemistry
1 answer:
AnnyKZ [126]3 years ago
6 0
The weight on earth of a book with a mass of 16 kg will be 65N
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An eclipse i’m pretty sure right? Lunar maybe?
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When jogging outside you accidently bump into a curb. Your feet stop but your body continues to move forward and you end up on t
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Answer:

Newton's First Law of Motion

Explanation:

Newton’s first law of motion is when an object can’t move or change their speed without some type of force. Inertia is included since is caused by unbalanced force.

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3 years ago
What conversion factor is present in almost all stoichiometry calculations?
luda_lava [24]
<h3><u>Answer;</u></h3>

Molar mass

<h3><u>Explanation</u>;</h3>
  • Stoichiometry involves the study of quantitative relationships between the amounts of reactants used and products formed by a chemical reaction.
  • A conversion factor is a ratio of coefficients found in a balanced reaction, which can be used to inter-convert the amount of products and reactants.
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8 0
3 years ago
5. A 4.44 L container holds 0.481 mol of O2 at 22.6°C. What is the pressure of the tank?
mamaluj [8]

Answer:  The pressure of the tank will be 2.63 atm

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = ?

V = Volume of gas = 4.44 L

n = number of moles = 0.481

R = gas constant =0.0821Latm/Kmol

T =temperature =22.6^0C=(22.6+273)K=295.6K

P=\frac{nRT}{V}

P=\frac{0.481mol\times 0.0821Latm/K mol\times 295.6K}{4.44L}=2.63atm

The pressure of the tank will be 2.63 atm

8 0
3 years ago
Read 2 more answers
PLEASE HELP I HAVE LIMITED TIME!!
n200080 [17]

Answer:

Explanation:

Si tomamos en cuenta el peso molecular del agua, que es equivalente a:

1 Átomo de H₂O

O = 16 gr/mol

H = 1 gr/mol

H₂O = 18 gr/mol

Teóricamente sabemos que en 1 mol de H2O habrá 18 gr.

 

Para obtener los moles presentes en 1 mg de H₂O, (como 1 gr = 1000 mg), decimos:

1 mol H2O …………………………..  18000 mg

       X          ……………………………   1 mg

X = 1 / 18000 = 5,56 X 10⁻⁵ moles de H20

 

Y para obtener la cantidad de moléculas presentes, de acuerdo a los moles, multiplicamos por el número de Avogadro (6,023 X 10²³ moléculas /mol)

Moléculas de H₂O = 5,56x 10⁻⁵ mol x 6,023 x 10²³

Moléculas de H₂O = 3,34488 x10¹⁹ moléculas de H₂O

En el copo de nieve habrá 3,34488 x 10¹⁹ moléculas de H₂O.

Espero que te sirva =)

3 0
3 years ago
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