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amid [387]
3 years ago
11

The top layer of a goose down sleeping bag has a thickness of 5.0 cm and a surface area of 1.0 m2. when the outside temperature

is -20o c, a body loses 20 cal/hr by heat conduction through the bag (which remains 35o c inside). assuming that a person is sleeping on an insulated pad that prevent heat loss to the ground, find the thermal conductivity of the goose down.

Physics
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

the thermal conductivity of the goose down = 0.0000210w/mK

Explanation:

The detailed steps from fourier's law of heat conduction is as shown in the attached file.

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increase

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3 years ago
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An astronaut is rotated in a horizontal centrifuge at a radius of 5.0 m. (a) What is the astronaut’s speed if the centripetal ac
sergeinik [125]

Explanation:

Given that,

Radius of circular path, r = 5 m

Centripetal acceleration, a=7g\ m/s^2

(a) Let v is the astronaut’s speed. The formula for the centripetal acceleration is given by :

a=\dfrac{v^2}{r}

v=\sqrt{ar}

v=\sqrt{7\times 9.8\times 5}

v = 18.5 m/s

(b) Let T denotes the time period. It is given by :

T=\dfrac{2\pi r}{v}

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T = 1.69 s

Let N is the number of revolutions. So,

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8 0
4 years ago
What is the difference in KE between a 52.5 kg person running 3.50 m/s and a 0.0200 kg bullet flying 450 m/s?
rusak2 [61]

Answer:

Ek = 1705.28 [J]

Explanation:

In order to solve this problem, we must remember that kinetic energy can be calculated by means of the following equation.

E_{k}=\frac{1}{2} *m*v^{2}

where:

m = mass [kg]

v = velocity [m/s]

Ek = kinetic energy [J] (Units of Joules)

<u>For the person running</u>

<u />E_{k} =\frac{1}{2}*52.2*(3.5)^{2} \\ E_{k} =319.72[J]<u />

<u />

<u>For the bullet</u>

<u />E_{k} =\frac{1}{2} *m*v^{2}<u />

<u />E_{k} =\frac{1}{2} *0.02*(450)^{2} \\E_{k}=2025 [J]<u />

<u />

The difference in Kinetic energy is equal to:

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8 0
3 years ago
18. _______ is a subtype of the continental climate.
irina1246 [14]
C humid subtropical
3 0
3 years ago
Suppose that the sound level of a conversation is initially at an angry 71 dB and then drops to a soothing 54 dB. Assuming that
Goryan [66]

Answer:

Explanation:

In the decibel scale , intensity of sound changes logarithmically as follows

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Putting the given values for 71 dB

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10^{-6.6} = 2π² x 504²xA²x 1.21 x  346

A² = 1.1978 x 10⁻¹⁶

A = 1.1 x 10⁻⁸ m

6 0
4 years ago
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