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Stells [14]
3 years ago
11

Based on how this sample looks, which term describes the matter that makes up granite?

Physics
2 answers:
EastWind [94]3 years ago
8 0

Answer:

C.Mixture

Explanation:

apex

agasfer [191]3 years ago
7 0

Answer:

C. mixture

Explanation:

A mixture is an impure substance. It has the following properties;

  • It's composition is indefinite
  • Their constituents retain their identities i.e. physical properties are retained
  • Constituents react differently to changed conditions
  • They can easily be separated into constituents by physical methods.

Granite is a rock. A rock is usually formed by a combination of different minerals.

Granite is made up of many compounds and so it is a mixture.

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What is the volume of the cone?
dezoksy [38]

Answer:

42.417 cm³

Explanation:

The formula to find the volume of a cone is :

V = \frac{1}{3} × π r² h

Here,

r ⇒ radius ⇒ 3 cm

h ⇒ height ⇒ 4.5 cm

<u>Let us find it now.</u>

V = \frac{1}{3} × π r² h

V = \frac{1}{3} × π × 3 × 3 × 4.5

V = \frac{1}{3} × π × 9 × 4.5

V = \frac{1}{3} × π × 9 × 4.5

V = \frac{1}{3} × π × 40.5

V = \frac{1}{3} × 3.142 × 40.5

V = \frac{1}{3} × 127.251

V = <u>42.417 cm³</u>

4 0
2 years ago
A compound microscope has an objective lens of focal length 1.40 cm and an eyepiece with a focal length of 2.20 cm. The objectiv
olchik [2.2K]

Answer:

magnification is - 159

objective distance is 3.85 cm

Explanation:

Given data

focal length f1 = 1.40 cm

focal length f2 = 2.20 cm

separated d = 19.6 cm

to find out

angular magnification and How far from the objective

solution

we know magnification formula that is

magnification = ( - L / f1 ) (D/f2)

here D = 25 cm put all value

magnification = ( - 19.6 / 1.40 ) (25/2.20)

magnification = - 159

and

now we apply lens formula

i/f = 1/q + 1/p

p = f2 = 2.20

so

q = f2 p / p -f2

q = 1.4(2.20) / ( 2.2 - 1.4 )

q = 3.85 cm

so objective distance is 3.85 cm

3 0
3 years ago
Which planet is 92,897,000 miles from the sun?
valentinak56 [21]
Earth is located approximately 92,897,000
3 0
3 years ago
An unknown solid weighs 31.6 n. when submerged in water, its apparent weight is 19.8 n. what is the specific gravity of the unkn
KATRIN_1 [288]

specific gravity of the unknown sample = 2.68

Explanation:

True weight of solid=31.6 N

Apparent weight=19.8 N

loss in weight= 31.6-19.8=11.8 N

Loss in weight= weight of the liquid displaced

so weight of water displaced= 11.8 N

now specific gravity= weight of object/ weight of liquid displaced

specific gravity= 31.6/11.8

specific gravity= 2.68

6 0
3 years ago
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