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Ilia_Sergeevich [38]
3 years ago
11

Two people are pushing a car to the right. The mass of the car is 1000.0 kg. One person applies a force of 275 N to the car, whi

le the other applies a force of 395 N. Find the the acceleration of the car (require two steps).

Physics
1 answer:
givi [52]3 years ago
7 0

Explanation:

Below is an attachment containing the solution.

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Which of the following has both kinetic and potential energy?
zysi [14]
It should be A.
A ball bouncing is moving so if it’s moving that means it has kinetic energy. It also has potential energy because when it hits the floor it kind of stops so it has potential.

-Hope this helps.
5 0
3 years ago
A speed skater moving across frictionless ice at 8.8 m/s hits a 6.0 m -wide patch of rough ice. She slows steadily, then continu
irina [24]

Recall that

<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>

where <em>u</em> and <em>v</em> are initial and final velocities, respectively; <em>a</em> is acceleration; and ∆<em>x</em> is the distance traveled (because the skater moves in only one direction).

So we have

(5.8 m/s)² - (8.8 m/s)² = 2 <em>a</em> (6.0 m)

<em>a</em> = ((5.8 m/s)² - (8.8 m/s)²) / (12 m)

<em>a</em> = -3.65 m/s²

4 0
3 years ago
To which group/family does each of these belong? A. Sulfur _________ B. Sodium _________ C. Argon _________ D. Silicon _________
ArbitrLikvidat [17]

Answer:

A. Sulfur _________ group 16 chalcogens

B. Sodium _________ group 1 alkali metals

C. Argon _________ group 18 noble gases

D. Silicon _________ group 14 carbon family

E. Chlorine _________ group 17 halogens

F. Phosphorus_________ group 15 pnicogens

7 0
2 years ago
According to special relativity, in which frames of reference does light in a vacuum travel at less than 3.0 108 m/s?
ch4aika [34]
The correct option is D.
According to special relativity, in no frame of reference does light in a vacuum travel at less than the speed of light, the speed of light in a vacuum is the same for any inertial reference frame.This fact remain valid no matter the speed of a light source relative to another observer.
6 0
3 years ago
Read 2 more answers
A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10
sashaice [31]

Answer:

Time interval;Δt ≈ 37 seconds

Explanation:

We are given;

Angular deceleration;α = -1.6 rad/s²

Initial angular velocity;ω_i = 59 rad/s

Final angular velocity;ω_f = 0 rad/s

Now, the formula to calculate the acceleration would be gotten from;

α = Change in angular velocity/time interval

Thus; α = Δω/Δt = (ω_f - ω_i)/Δt

So, α = (ω_f - ω_i)/Δt

Making Δt the subject, we have;

Δt = (ω_f - ω_i)/α

Plugging in the relevant values to obtain;

Δt = (0 - 59)/(-1.6)

Δt = -59/-1.6

Δt = 36.875 seconds ≈ 37 seconds

6 0
4 years ago
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