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White raven [17]

3 years ago

11

You are in a spaceship far outside our solar system. Inside your spaceship there is not gravity and no air (and therefore no air

resistance). If you toss a ball across the spaceship, how do Newton's laws predict its motion will change as it moves?

2 answers:

True [87]3 years ago

8 0

According to Newton's first law, without any forces bodies save their state of rest or motion. Since you tossed a ball, it will continue going along direction of the force you initially exerted in a straight line. What would happen after collision with the spaceship's walls is frankly speaking unpredictable because you don't know configuration of the surfaces that the ball will hit, but what we can say is that after each collision the ball will move in straight lines.

Andreyy893 years ago

6 0

Newtons first law: The ball will go at constant speed without stopping

Newtons third law: The ball will also push back at you causing you to go back as well

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A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic fr

Zinaida [17]

Answer:

The initial speed of bullet is "164 m/s".

Explanation:

The given values are:

mass of bullet,

$m'=9.00 \ g$

or,

$=0.009 \ kg$

mass of wooden block,

$m=1.20 \ kg$

speed,

$s=0.390 \ m$

Coefficient of kinetic friction,

$\mu=0.20$

As we know,

The Kinematic equation is:

⇒ $v^2=u^2+2as$

then,

Initial velocity will be:

⇒ $u=v^2-2as$

$=v^2-2 \mu gs$

On substituting the given values, we get

⇒ $u=\sqrt{0-2\times 0.20\times 9.8\times 0.390}$

$=\sqrt{-1.5288}$

$=1.23 \ m/s$

As we know,

The conservation of momentum is:

⇒ $mu=m'u'$

or,

⇒ Initial speed, $u'=\frac{mu}{m'}$

On substituting the values, we get

⇒ $=\frac{1.20\times 1.23}{0.009}$

⇒ $=\frac{1.476}{0.009}$

⇒ $=164 \ m/s$

3 0

2 years ago

if a bowling ball hits a wall a force of 6 N, the wall exerts a force of how much back. on the bowling ball

Ray Of Light [21]

There has to be 6 N for a reactant

5 0

2 years ago

does the wavelength of the sound increase, decrease, or stay the smae as the musician changes from the first sound to the second

Naya [18.7K]

Decrease K k kk kk k k k

8 0

2 years ago

Read 2 more answers

"My distance to the center of the earth is about 4000 miles when I am on the surface. If I go to a height of 8000 miles above th

lord [1]

Given,

Distance from the surface to the center of the earth, d=4000 miles

Distance from the center to you at a height of 8000 miles, a= 8000+4000=12000 miles

The gravitational force acting on a person at the surface is equal to his weight.

From Newton's Universal Law of Gravitation, the gravitational force is

$F=\frac{G\times M\times m}{r^2}$

Where G is the gravitational constant, M is the mass of the earth, m is the mass of the object/person, r is the distance between the center of the earth and the object/person

At the surface, this force is equal to the weight of the person, W=mg

i.e.

$F_s=\frac{G\times M\times m}{d^2}=W$

On substituting the of d,

$W=\frac{\text{GMm}}{4000^2}$

At a height of 8000 miles from the surface, the gravitational force is equal to,

$F_a=\frac{GMm}{12000^2}$

On dividing the above two equations,

$\frac{F_a}{W}=\frac{4000^2^{}}{12000^2}=\frac{1}{9}$

Therefore,

$F_a=\frac{1}{9}W$

Therefore at a height of 8000 miles above the surface of the earth, the force of gravity becomes 1/9 time your weight.

5 0

7 months ago

Ana walks from 4 m to 200 cm. Which of the following statements is true about

Gemiola [76]

Distance=2m

because 200cm = 2m
so 4m-2m=2m

3 0

2 years ago