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hram777 [196]
3 years ago
15

Miners discover a new vein of metal in the mine they are excavating. They send a sample to your lab so you can determine what ty

pe of metal it is. You heat up a 2 kg block of the unknown metal from room temperature of 298 K until it melts at 1768 K. You measure that it takes 1.24 x 10^6 J of energy to melt the block. Use the specific heats of various metals shown below to determine what metal the miners have discovered.
Aluminum: 904 J kg-1 K-1
Nickel: 445 J kg-1 K-1
Copper: 384 J kg-1 K-1
Cobalt: 421 J kg-1 K-1
Titanium: 520 J kg-1 K-1
A. Cobalt
B. Copper
C. Aluminum
D. Nickel
Chemistry
1 answer:
svp [43]3 years ago
8 0
Answer: option A. Cobalt

Explanation:

1) Data:

Q = 1.24 × 10⁶ J
m = 2 kg
Tf = 1768 K
Ti = 298 K
Cs = ?

2) Formula:

Q = m Cs ΔT
ΔT = Tf - Ti = 1,768K - 298K = 1,470K

3) Calculations:

i) Solve for Cs:

Cs = Q / [ m ΔT]

ii) Substitute the data:

Cs = 1.24 × 10⁵ J / [ 2kg (1768K - 298K) ] = 421 J / (kg K)

4) Compare with the specific heats (Cs) of the vaious metals given and you find that it is Cobalt.

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which two human body system function together to distribute oxygen for use in cellular process throughout the body
lukranit [14]
The circulatory system and the respiratory system; The respiratory system takes in the oxygen which then goes into our bloodstream to help our cells convert it into ATP energy.
7 0
3 years ago
A postulate of the kinetic molecular theory is listed.
valina [46]

Answer:

Postulate: Gas particles are extremely small and are far apart.

The activities can be used to demonstrate the postulate is :

<u>Observing colored gas spreading into an inverted jar placed on top of a jar containing the gas</u>

<u />

Explanation:

colored gas spreading into an inverted jar placed on top of a jar containing the gas:

This occur because of two reasons:

1. <em><u>The Gaseous particles are largely spaced . There is large distance between the gases molecule</u></em>

<em><u>2. The gases are in continuous motion . Hence they posses very high kinetic energy . This is the reason they mixes quickly if placed in a jar.</u></em>

<em><u>This occur by the process of diffusion. </u></em>

Diffusion of Gases: The intermixing of particles from the region of high concentration to low concentration.

The coloured gas goes into the space between the gaseous molecule present in the jar.(Gases are far apart)

As soon as the coloured gas is mixed in the jar , It spread quickly by diffusion because , The gaseous particles are extremely small and are far apart.

5 0
3 years ago
"a basic experiment involves a minimum of ________ participant group(s)."
3241004551 [841]
Answer: TWO.

At least two groups: treatment group and control group.

The treatment group is that is exposed to the different levels of the independent variable ( a medication for example), while the control group is not treated, so the researchers can compare the effect of the medication.
5 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is
Pie

Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

Step 5: Calculate the limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

7 0
3 years ago
Not sure what to do can you help
NeTakaya

sorry i don't know the answer i'm really sorry

7 0
2 years ago
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