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k0ka [10]
3 years ago
9

One of the dangers of tornados and hurricanes is the rapid drop in air pressure that is associated with such storms. Assume that

the air pressure inside of a sealed house is 1.02 atm when a hurricane hits. The hurricane rapidly decreases the external air pressure to 0.910 atm. A square window in an outside wall of the house measures 2.02 m on each side. What net force (directed outwards) is exerted on this window? (1 atm = 1.01 × 105 Pa.)
Physics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

     F = 8.25 10⁴ N

Explanation:

The definition of pressure is

      P = F / A

      F = P A

Let's use Newton's second law in the window

      F = F₁- F₂

      F = P₁ A - P₂  A

      F = (P₁ -P₂)  A

The area of ​​a square window is

     A = L²

     F = (P₁ -P₂) L²

Let's reduce the magnitudes to the SI system

     P₁ = 1.2 atm (1.01 10⁵ Pa / 1 atm) = 1.212 10⁵ Pa

     P₂ = 0.910 10⁵ atm = 0.9191 10⁵ Pa

Let's calculate

      F = (1.1212 - 0.9191) 10⁵ 2.02²

     F = 0.8246 10⁵ N

     F = 8.25 10⁴ N

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On a cold winter day, a penny (mass 2.50 g) and a nickel (mass 5.00 g) are lying on the smooth (frictionless) surface of a froze
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Answer:

0.78333 m/s in the opposite direction

1.566 m/s in the same direction

Explanation:

m_1 = Mass of penny = 0.0025 kg

m_2 = Mass of nickel = 0.005 kg

u_1 = Initial Velocity of penny = 2.35 m/s

u_2 = Initial Velocity of nickel = 0 m/s

v_1 = Final Velocity of penny

v_2 = Final Velocity of nickel

As momentum and Energy is conserved

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

{\tfrac {1}{2}}m_{1}u_{1}^{2}+{\tfrac {1}{2}}m_{2}u_{2}^{2}={\tfrac {1}{2}}m_{1}v_{1}^{2}+{\tfrac {1}{2}}m_{2}v_{2}^{2}

From the two equations we get

v_{1}=\frac{m_1-m_2}{m_1+m_2}u_{1}+\frac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\frac{0.0025-0.005}{0.0025+0.005}\times 2.35+\frac{2\times 0.5}{0.4005+0.5}\times 0\\\Rightarrow v_1=-0.78333\ m/s

The final velocity of the penny is 0.78333 m/s in the opposite direction

v_{2}=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 0.0025}{0.0025+0.005}\times 2.35+\frac{0.005-0.0025}{0.005+0.0025}\times 0\\\Rightarrow v_2=1.566\ m/s

The final velocity of the nickel is 1.566 m/s in the same direction

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