Question

A hair spray can has a volume of 565 mL. If the can is at 42 C and 5 atm, what volume would the hair spray occupy at STP?

Answer 1

Answer:

$V_2 = 2.447$ atm

Explanation:

As we know that

$PV = nRT$

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin  

R is the gas constant  $R = 0.08206$

V is the volume in liters

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

Substituting the given values in above equation, we get -

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\frac{5*0.565}{315.15} = \frac{1*V_2}{273}$

On rearranging, we get

$\frac{5*0.565*273}{315.15} = V_2\\V_2 = 2.447$

$V_2 = 2.447$ atm