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IRINA_888 [86]
4 years ago
10

Pulleys and Belts. In a pulley system, pulley A is moving at 1500 rpm and has a diameter of 15 in. Three pulleys, B, C, and D, a

ll of different sizes, are attached to a single output axle. Speed and torque output are changed within the system by moving the drive belt between pulleys B, C, and D.. 1.A speed of 1750 rpm is required when the drive belt is connected to pulley B. What is the diameter of pulley B? . 2.A speed of 2000 rpm is required when the drive belt is connected to pulley C. What is the diameter of pulley C? . 3.A speed of 3250 rpm is required when the drive belt is connected to?
Physics
2 answers:
NeTakaya4 years ago
8 0

For this question I would use the similarities between pulley A, to each pulley of the question. 


<span>1. A speed of 1750 rpm is required when the drive belt is connected to pulley B. What is the diameter of pulley B?</span>

15inches / 1500rpm = (x<span>) inches / 1750rpm</span>

(x)  = 15 inches * 1750 rpm / 1500rpm

(x) = 17.5 inches 

2.A speed of 2000 rpm is required when the drive belt is connected to pulley C. What is the diameter of pulley C?

15inches / 1500rpm = (x) inches / 2000rpm

(x)  = 15 inches * 2000 rpm / 1500rpm

(x) = 20 inches 

3. A speed of 3250 rpm is required when the drive belt is connected to?

15inches / 1500rpm = (x) inches / 3250rpm

(x)  = 15 inches * 3250 rpm / 1500rpm

(x) = 32.5 inches 

son4ous [18]4 years ago
3 0

Answer:

1. A speed of 1750 rpm is required when the drive belt is connected to pulley B. What is the diameter of pulley B?

15inches / 1500rpm = (x) inches / 1750rpm

(x)  = 15 inches * 1750 rpm / 1500rpm

(x) = 17.5 inches 

2.A speed of 2000 rpm is required when the drive belt is connected to pulley C. What is the diameter of pulley C?

15inches / 1500rpm = (x) inches / 2000rpm

(x)  = 15 inches * 2000 rpm / 1500rpm

(x) = 20 inches 

3. A speed of 3250 rpm is required when the drive belt is connected to?

15inches / 1500rpm = (x) inches / 3250rpm

(x)  = 15 inches * 3250 rpm / 1500rpm

(x) = 32.5 inches 

Explanation:

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3 0
4 years ago
Read 2 more answers
A projectile is fired with an initial velocity of 450 feet per second at an angle of 70° with the horizontal.
pav-90 [236]
<h2>After 26.28 seconds projectile returns 26.28 seconds.</h2>

Explanation:

Initial velocity = 450 ft/s = 137.16 m/s

Angle, θ = 70°

Consider the vertical motion of projectile,

When the projectile return to the ground we have

           Displacement, s = 0 m

           Acceleration, a = -9.81 m/s²

            Initial velocity, u = 137.16 x sin70 = 128.89 m/s

Substituting in s = ut + 0.5 at²

                s = ut + 0.5 at²

                0 = 128.89 x t + 0.5 x (-9.81) x t²

                t² - 26.28 t = 0

                t ( t- 26.28) = 0

               t = 0 s or t = 26.28 s

After 26.28 seconds projectile returns 26.28 seconds.

5 0
3 years ago
What is the mechanical advantage of a pulley system​
tatuchka [14]

Answer:

Pulleys accomplish 2 separate operations throughout the computer controlled additional benefit technologies listed elsewhere here.

Explanation:

  • If indeed the pulley would be connected to that same attachment point, these are named a corrected pendulum or perhaps a change in direction. Its job should be to reverse the trajectory of that same rope pull.  
  • Unless the pulley would be connected to that same load, this same pulley seems to be a detachable as well as a mechanical additional benefit.
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3 years ago
One of the most important properties of materials in many applications is strength. Two of the qualitative measures of the stren
katrin2010 [14]

To solve this exercise it is necessary to take into account the concepts related to Tensile Strength and Shear Strenght.

In Materials Mechanics, generally the bodies under certain loads are subject to both Tensile and shear strenghts.

By definition we know that the tensile strength is defined as

\sigma = \frac{F}{A}

Where,

\sigma =Tensile strength

F = Tensile Force

A = Cross-sectional Area

In the other hand we have that the shear strength is defined as

\sigma_y = \frac{F_y}{A}

where,

\sigma_y =Shear strength

F_y = Shear Force

A_0 =Parallel Area

PART A) Replacing with our values in the equation of tensile strenght, then

311*10^6 = \frac{F}{(15*10^{-6})(30*10^{-2})}

Resolving for F,

F= 1399.5N

PART B) We need here to apply the shear strength equation, then

\sigma_y = \frac{F_y}{A}

210*10^6 = \frac{F_y}{15*10^{-6}30*10^{-2}}

F_y = 945N

In such a way that the material is more resistant to tensile strength than shear force.

6 0
3 years ago
4. Explain how states of matter change in regards to<br> a. Temperature-<br> b. Pressure-
Alina [70]
Temperature can change the state from solid to liquid causing it to melting, liquid to gas causing vaporization or a solid to a gas causing sublimation. Pressure alone cannot change the state of matter.
5 0
3 years ago
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