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ser-zykov [4K]
2 years ago
15

Which of the following metric system units is used when measuring large quantities of water?

Physics
1 answer:
Karolina [17]2 years ago
7 0

Answer:

I want to say Liters but not 100% sure

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A robot character that can transform into a car
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3 years ago
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Which of the following takes place in the combustion chamber of a gas turbine engine?A. A glow plug is used to add enough heat t
erica [24]

Answer:

Fuel oil is mixed with a proper portion of compressed air

Explanation:

A gas turbine has three main part, which are

  • combustion chamber
  • air compressor
  • power turbine

The combustion chamber is responsible for mixing fuel with a proper portion of compressed air.

The air compressor supplies air in sufficient quantity to satisfy the requirements of the combustion chamber

The power turbine produces the power to drive the air compressor.

6 0
3 years ago
A phone cord is 4.67 m long. The cord has a mass of 0.192 kg. A transverse wave pulse is produced by plucking one end of the tau
Olegator [25]

Answer:

91.017N

Explanation:

Parameters

L=4.67m, m=0.192kg, t = 0.794s, The pulse makes four trips down and back along the cord, we have 4 +4 =8 trips( to and fro)

so N= no of trips = 8, From  Wave speed(V) = N *L/t , we have :

V= 8*4.67/0.794 = 47.0529 m/s.

We compute the cords mass per length,  Let it be P

P = M/L = 0.192/4.67 = 0.04111 kg/m

From  T = P * V^2  where T = Tension, we have

T = 0.04111 * (47.0529)^2

T =  91.017N.

The tension in the cord is 91.017N

3 0
3 years ago
Among of energy in a photon of light is proportional to the
Setler [38]
D. frequency of the corresponding light wave
5 0
3 years ago
In the ENGR 10 lab (E391), there are 50 long light bulbs (P=100 W) and 30 regular bulbs (P=60 W). How much energy is consumed li
Alenkinab [10]

Answer:

Total energy saving will be 0.8 KWH

Explanation:

We have given there are 50 long light bulbs of power 100 W so total power of 50 bulb = 100×50 = 5000 W = 5 KW

30 bulbs are of power 60 W

So total power of 30 bulbs = 30×60 = 1800 W = 1.8 KW

Total power of 80 bulbs = 1.8+5 = 6.8 KW

Total time = 3 hour

We know that energy E=power\times time=6.8\times 3=20.4KWH

Now power of each CFL bulb = 25 W

So power of 80 bulbs = 80×25 = 2000 W = 2 KW

Energy of 80 bulbs = 2×3 = 6 KWH

So total energy saving = 6.8-6 = 0.8 KWH

6 0
3 years ago
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