Answer: 0.08K
Explanation:
When temperature changes, the corresponding change in thermal energy of a gas is given by:
ΔE (thermal) = 3/2nRΔT
Defining the parameters:
ΔE (thermal) = Increase in thermal energy of the mono atomic gas = 1.0J
n = number of moles of the gas = 1.0mol
R = Ideal gas constant = 8.314J/mol/K
ΔT = change in temperature. This is what we need to find.
Rearranging the equation to make ΔT subject of the formula,
ΔT= 2 x ΔE (thermal) / (3 x n x R)
Therefore, ΔT = 2 x 1.0J / (3 x 1.0mol x 8.314J/mol/K)
ΔT = 2.0J / 24.942J/K
ΔT = 0.0802K
ΔT = 0.08K
The temperature change of 1.0mol of a monoatomic gas if its thermal energy is increased by 1.0J is 0.08K.
