I need more to answer this
Λ = 3*10^8 / 9*10^8 = 1/3 m
no. of wavelengths = 60/(1/3) = 180
Answer:
The time taken by the satellite to orbit earth at its surface, t = 1.66 hr
Explanation:
Given data,
The velocity of the satellite, v = 15000 miles/hr
The distance of travel, d = 24901 miles,
It is equal to the circumference of earth,
So the time taken by the satellite to orbit earth at its surface,
v = d/t
t = d/v
Substituting the given values in the above equation,
t = 24901 / 15000
= 1.66 hr
Hence, the time taken by the satellite to orbit earth at its surface, t = 1.66 hr
Answer: 704
Explanation:Vi = 0 m/s
vf = 65 m/s
a = 3 m/s2
d = ??
vf2 = vi2 + 2*a*d
(65 m/s)2 = (0 m/s)2 + 2*(3 m/s2)*d
4225 m2/s2 = (0 m/s)2 + (6 m/s2)*d
(4225 m 2/m2)/(6 m/s2) = d
d = 704 m
Answer:
D. mass to see how it affected stretch length of a rubber band
