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olchik [2.2K]
2 years ago
9

The human ear is sometimes called a Fourier analyzer. What does this mean and why is it an apt description? 1. Our ears can sort

out the individual sine waves from a mixture of two or more sine waves, so we hear the pure tones that make up a complex tone. 2. Our ears measure the intensity of sound, which is just what a Fourier analyzer does. 3. Our ears can measure the speed of sound. 4. Our ears have nothing to do with a Fourier analyzer
Physics
2 answers:
tamaranim1 [39]2 years ago
6 0

Answer:

1. Our ears can sort out the individual sine waves from a mixture of two or more sine waves, so we hear the pure tones that make up a complex tone.

Explanation:

A complex tone is a sound wave that consist of two or more forms of audible sound frequencies. Sound wave is a mechanical wave that is longitudinal, and could be represented by a sine wave because of it sinusoidal manner of propagation.

A Fourier analyzer can be used to differentiate individual sine waves from a combination of two or more of it; which is as the same function performed by human ear. To the human ear, a sound wave that consist of more than one sine wave will have perceptible harmonics which would be distorted and turn to a noise.

Thus, the human ear makes it possible to hear the pure tones that make up a complex tone.

Sliva [168]2 years ago
3 0

Answer:

1. A Fourier analyzer sorts out the individual sine waves from a mixture of two or more sine waves, so we hear the pure tones that make up a complex tone.

Explanation:

Fourier analysis is a technique that is used to determine which sine waves constitute a given signal, i.e. to deconstruct the signal into its individual sine waves.  It is the process of decomposing a periodic function into its constituent sine or cosine waves.

What goes on inside our ears is a mathematical process called a Fourier transform. In the ear, there's a combination of different waves, Fourier analysis identifies contributions at different frequencies, allowing us to reconstruct the individual signals that go into it.

A complex tone perceived by the air is is an individual sine wave that the ear, by acting as a Fourier analyzer, decomposes to serious of sine waves that we hear as pure tones.

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dsp73

Answer:

Explanation:

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As she accelerates faster, the air resistance force <u><em>increases</em></u>. It is now the <u><em>same </em></u>as her weight. She now moves at a <u><em>constant</em></u> speed because the <u><em>resultant </em></u>force acting on her is zero. She is now at her <u><em>terminal </em></u>velocity.

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4 0
2 years ago
A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
tensa zangetsu [6.8K]

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4       ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28   momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

5 0
2 years ago
Suppose that the electric field in the Earth's atmosphere is E = 8.60 101 N/C, pointing downward. Determine the electric charge
asambeis [7]

Answer:

q = 3.87 x 10⁵ C

Explanation:

given,

Electric field, E = 8.60 x 10¹ = 86 N/C

radius of earth, R = 6371 Km = 6.371 x 10⁶ m

Coulomb constant, K = 9 x 10⁹ N · m²/C²

Charge on the earth = ?

the electric field at the point

E =\dfrac{kq}{r^2}

q =\dfrac{Er^2}{k}

inserting all the values

q =\dfrac{86\times (6.371\times 10^6)^2}{9\times 10^{9}}

      q = 3.87 x 10⁵ C

The electric charge on the earth is equal to 3.87 x 10⁵ C

4 0
3 years ago
In an electromagnetics lab, you are studying two coils which have a mutual inductance of M=300 mH. Suppose that the current in t
Firdavs [7]

Answer:

Explanation:

Given that,

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M = 300mH = 300 × 10^-3 H

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∆I = I_2 - I_1 = 10 - 2.8

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Within the time 300ms

t = 300ms = 300 × 10^-3

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Second Coil resistance

R_2 = 0.4 ohms

We want to find the current in the second coil,

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ε = 0.3 × 7.2 / 0.3

ε = 7.2 Volts

Now, this is the voltage across both coils,

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ε = I_2•R_2

0.72 = I_2 • 0.4

I_2 = 0.72 / 0.4

I_2 = 1.8 Amps

The current in the second coil is 1.8A

7 0
3 years ago
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Work= force*distance
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Work= 480 J (joules)
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5 0
3 years ago
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