Answer:
E = 12.25 x 10³ N/C = 12.25 KN/C
Explanation:
In order to balance the weight of the object the electrostatic force due to the electric field must be equal to the weight of the body or charge. Therefore,
Electrostatic Force = Weight
E q = mg
where,
E = Electric Field = ?
m = Mass of the Charge = 5 x 10⁻³ kg
g = acceleration due to gravity = 9.8 m/s²
q = magnitude of charge = 4 μC = 4 x 10⁻⁶ C
Therefore,
E(4 x 10⁻⁶ C) = (5 x 10⁻³ kg)(9.8 m/s²)
E = 0.049 N/4 x 10⁻⁶ C
<u>E = 12.25 x 10³ N/C = 12.25 KN/C</u>
Explanation:
The object's weight on Earth is 5.0 N, so its mass is:
F = ma
5.0 N = m (10 m/s²)
m = 0.50 kg
The acceleration on the moon is g/6 = (10 m/s²) / 6 = 1.67 m/s².
The velocity it reaches after 3.0 seconds is:
v = at + v₀
v = (1.67 m/s²) (3.0 s) + (0 m/s)
v = 5 m/s
So the momentum is:
p = mv
p = (0.50 kg) (5 m/s)
p = 2.50 kg m/s
Answer:
a) Shadow distance
10 cm in front of the mirror.
b) Zoom in the shadow
The shadow formed is the same height as the object and is placed also at the centre of curvature of the mirror as shown in the attached image to this solution.
c) The nature of the shadow
The shadow formed is real, inverted, same size as the object and formed at the centre of curvature.
Explanation:
English Translation
Objects as high as 3 cm are placed at a distance of 10 cm in front of a concave mirror with 10 cm curvature. Determine:
a) Shadow distance
b) Zoom in the shadow
c) The nature of the shadow
Solution
The mirror equation is given as
(1/f) = (1/v) + (1/u)
f = focal length of the mirror = (radius of curvature)/2 = 10/2 = 5 cm
v = image distance = ?
u = object distance = 10 cm
We can then calculate the shadow' s distance from the mirror thus
(1/5) = (1/v) + (1/10)
(1/v) = 0.2 - 0.1 = 0.1
v = (1/0.1) = 10 cm
b) Zoom in the shadow
Since the object is placed at the centre of curvature, as shown in the attached image, the image is formed at a point of intersection of rays. The image formed is the same height as the object and is placed also at the centre of curvature of the mirror.
c) The nature of the shadow
Since the mirror is a concave mirror, the image is real and formed in front of the mirror. The image is also inverted and formed at the centre of curvature of the mirror.
Hope this Helps!!!
Answer:
Hi there! I have only the procedure and the scientific names of the creatures. Hope this helps!
Procedure
I studied the physical features of ten creatures and classified them using the key. I completed each section below and recorded the creature's scientific name in the data section.
The Creatures Scientific Names:
1
Fuzzus tallywag
2
Fuzzus pointilus
3
Silkus duosquirmus
4
Fuzzus chompilus
5
Silkus stretchilus
6
Silkus tallyhas
7
Fuzzus feelzalot
8
Silkus monosquirmus
9
Fuzzus squarilus
10
Silkus monowrestle
Have a thrilling Thursday!
~Lola
Answer:24
Explanation:
First you need to calculate the acceleration, for this use can use the following formula Force (F) = Mass (M) x Acceleration (A). If we extract A out of this, you can get the following equation A = F/M = 4/0.5 = 8 m/s^2. So, the object accelerates each second by 8 m/s, if the object does this for 3 second, the velocity would be 8 x 3 = 24