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ICE Princess25 [194]

3 years ago

13

A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 28.7 g. What is the density of that mineral frag

ment?

2 answers:

statuscvo [17]3 years ago

8 0

P=M÷V
p=28.7÷5.74
p=5

The density is 5.

Shkiper50 [21]3 years ago

7 0

Explanation:

Density is defined as mass per unit volume.

Mathematically, $d = \frac{m}{V}$

where, d = density

m = mass

V = volume

It is given that volume is $5.74 cm^{3}$ and mass is 28.7 g. Then calculate the density as follows.

$d = \frac{m}{V}$

= $\frac{28.7 g}{5.74 cm^{3}}$

= $5 g/cm^{3}$

Therefore, we can conclude that the density of that mineral fragment is $5 g/cm^{3}$ .

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$S_2O=\sqrt{(S_1S_2)^2+(S_1O)^2}\\S_2O=\sqrt{(3)^2+(4)^2}\\S_2O=\sqrt{9+16}\\S_2O=\sqrt{25}\\S_2O=5m$

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λ is wavelength which is given as

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f is the frequency of the sound which is to be calculated.

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for minimum frequency $f_1$ , k=1

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