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DENIUS [597]
3 years ago
6

Sort the resources into the correct categories.

Chemistry
1 answer:
Lapatulllka [165]3 years ago
3 0

Answer:

Renewable Resources: are considered unlimited, are replaced faster than used.

Nonrenewable Resources: are used more quickly than replaced, have fixed amounts, cannot be replaced in a short time.

Explanation:

Renewable resources are natural resources that are able to naturally regenerate themselves, hence, they are considered to be unlimited. They are usually replaced faster than they are used because they have a short regeneration time. A good example is the solar energy.

Nonrenewable resources are those natural resources that cannot naturally regenerate and when they do, it takes a very long time (usually millions of years). They are therefore used at a much faster rate than they are being replaced and their natural deposits are more or less fixed due to the long regeneration time. A good example is the crude oil deposit.

Hence:

Renewable Resources: are considered unlimited, are replaced faster than used.

Nonrenewable Resources: are used more quickly than replaced, have fixed amounts, cannot be replaced in a short time.

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ivann1987 [24]
Boiling liquids that want to escape gas
4 0
3 years ago
What is the voltage in a circuit is the current is 3 amps and the resistance is 3 ohms
ozzi

Answer:

9

Explanation:

V=I*R

3*3

Thats the answer

7 0
3 years ago
Oh, no! You just spilled 85.00 mL of 1.500 M sulfuric acid on your lab bench and need to clean it up immediately! Right next to
vredina [299]

Explanation:

We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.

   H_2SO_4(aq) + 2NaHCO_3(s) \rightarrow Na2SO_4(aq) + 2H_2O(l) + 2CO_2(g)

Next we will calculate how many moles of H_2SO_4 are present in 85.00 mL of 1.500 M sulfuric acid.

As,       Molarity = \frac{\text{moles of solute}}{\text{liters of solution
}}

            1.500 M = \frac{n}{0.08500 L
}

                    n = 0.1275 mol H_2SO_4

Now set up and solve a stoichiometric conversion from moles of H_2SO_4  to grams of NaHCO_3. As, the molar mass of NaHCO_3 is 84.01 g/mol.

 0.1275 mol H_2SO_4 \times (\frac{2 mol NaHCO_3}{1 mol H_2SO_4}) \times (\frac{84.01 g NaHCO_3}{1 mol NaHCO_3})

                 = 21.42 g NaHCO_3

So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.

4 0
3 years ago
Balancing Equations. How many of the element should I drag to the center?
babunello [35]

Answer:

4FeS + 7O₂ ----> 2Fe₂O₃ + 4SO₂

Explanation:

You have to drag the elements shown on the right under the formula.  For example, you would have to drag 4 of the FeS molecules under the 4FeS text in the formula.  Then place 7 O₂ molecules under the 7O₂ text, etc.

8 0
3 years ago
What is the difference between the hybridization of carbon atoms’ valence orbitals in saturated and unsaturated hydrocarbons?
ANEK [815]

Answer:

Type of hybridisation

Explanation:

For example , saturated hydrocarbons have sp3 hybridisation while unsaturated hydrocarbons have either sp2 or sp hybridisation.

Example: Ethane( C2H6) has sp3 hybridisation and ethene(C2H4) has sp2 hybridisation and Ethyne(C2H2) has sp hybridization.

7 0
3 years ago
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