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musickatia [10]
3 years ago
15

How many millimeters of 1.25 M Copper(2) sulfate, CuSO4, will contain 55.75g CuSo4

Chemistry
1 answer:
Shkiper50 [21]3 years ago
8 0

Answer:

280 mL

Explanation:

Given data:

Mass of CuSO₄ = 55.75 g

Molarity of CuSO₄ = 1.25 M

Volume of CuSO₄ = ?

Solution:

First of all we will calculate the number of moles.

Number of moles:

Number of moles = mass / molar mass

Number of moles = 55.75 g/ 159.6 g/mol

Number of moles = 0.35 mol

Volume of CuSO₄:

Molarity = number of moles / volume in litter

1.25 M = 0.35 mol / volume in litter

Volume in litter = 0.35 mol / 1.25 M

Volume in litter = 0.28 L

Volume in milliliter:

0.28 L × 1000 mL/ 1 L = 280 mL

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Predidt the direction and the relative value of the dipole moment of the following bond: C-Cl
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Write the isotopic symbol for the following (show your work) a) An isotope of iodine whose atoms have 78 neutrons b) An isotope
morpeh [17]

<u>Answer:</u>

<u>For a:</u> The isotopic representation of iodine is _{53}^{131}\textrm{I}

<u>For b:</u> The isotopic representation of cesium is _{55}^{137}\textrm{Cs}

<u>For c:</u> The isotopic representation of strontium is _{38}^{52}\textrm{Sr}

<u>Explanation:</u>

The isotopic representation of an atom is: _Z^A\textrm{X}

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Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

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We are given:

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Thus, the isotopic representation of cesium is _{55}^{137}\textrm{Cs}

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We are given:

Number of neutrons = 52

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