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musickatia [10]
3 years ago
15

How many millimeters of 1.25 M Copper(2) sulfate, CuSO4, will contain 55.75g CuSo4

Chemistry
1 answer:
Shkiper50 [21]3 years ago
8 0

Answer:

280 mL

Explanation:

Given data:

Mass of CuSO₄ = 55.75 g

Molarity of CuSO₄ = 1.25 M

Volume of CuSO₄ = ?

Solution:

First of all we will calculate the number of moles.

Number of moles:

Number of moles = mass / molar mass

Number of moles = 55.75 g/ 159.6 g/mol

Number of moles = 0.35 mol

Volume of CuSO₄:

Molarity = number of moles / volume in litter

1.25 M = 0.35 mol / volume in litter

Volume in litter = 0.35 mol / 1.25 M

Volume in litter = 0.28 L

Volume in milliliter:

0.28 L × 1000 mL/ 1 L = 280 mL

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Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).

pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.

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Replacing in the definition of pOH:

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In summary, the pOH of the aqueous solution is 1.14

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