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Evgesh-ka [11]
3 years ago
11

you rent a car in germany with a gas mileage rating of 12.8 km/L. What is the rating in miles er hours.

Chemistry
1 answer:
QveST [7]3 years ago
5 0

Answer:

I think it would be 30.10 mpg

Explanation:

The conversion rate would be 1 : 2.35

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What is the concentration of a solution of HCl in which a 10.0 mL sample of acid required 50.0 mL of 0.150 M NaOH for neutraliza
puteri [66]

Answer:

The answer is 0.75M HCl

Explanation:

To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:

To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:

C1V1 = C2V2

C1 = concentration of acid

C2 = concentration of base

V1 = volume of acid

V2 = volume of base

From the information supplied in the question:

concentration of acid (HCl) is the unknown

volume of acid (HCl) = 10ml

concentration of base (NaOH) = 0.15M

volume of base (NaOH) = 50ml

C1 x 10ml = 0.15M x 50ml

C1 x 10 = 7.5

divide both side by 10

C1 = 0.75M

concentration of acid (HCl) is 0.75M

5 0
3 years ago
A concentration cell is constructed by using the same half-reaction for both the cathode and anode. What is the value of standar
Akimi4 [234]

Solution :

A cell that is concentrated is constructed by the same half reaction for the anode as well as he cathode.

We know,

In a standard cell,

the reduction half cell reaction is :

$Ag^+(aq)+e^- \rightarrow Ag(s) E^0 = -0.80 \ V$

The oxidation half ell reaction :

$Ag(s) \rightarrow Ag^+(aq) + e^- \ E^0= +0.80 \ V$

Thus the complete reaction of the cell is :

$Ag^+(aq)+ Ag(s) \rightarrow Ag^+(aq)+Ag(s)$

$E^0 $ cell = $E_R - E_L = 0.00  \ \text{volts}$

7 0
2 years ago
When each of the following pairs of aqueous solutions is mixed, does a precipitation reaction occur? If so, write balanced molec
Aleks04 [339]

Yes, a precipitation process does take place here. BaCO₃ and KOH are the byproducts of this double displacement reaction, and since BaCO₃ is soluble in solution, it precipitates as a solid.

Molecular: Ba(NO₃)₂(aq) + K₂CO₃(aq) → 2K⁺(aq) + 2NO₃¯(aq) + BaCO₃(s) ⬇︎

The complete ionic reaction can be written as follows:

Ba²⁺(aq) + 2NO₃¯(aq) + 2K⁺(aq) + CO₃²¯(aq) → 2K⁺(aq) + 2NO₃¯(aq) + BaCO₃(s) ⬇︎

All the ions in solution have been written out. Now, on to the net ionic equation:

Ba²⁺(aq) + CO₃²¯(aq) → BaCO₃(s) ⬇︎

<h3>what is precipitation?</h3>

Any liquid or frozen water that condenses in the atmosphere and falls to the ground is known as precipitation. Snow, sleet, and rain are just a few of the variations. One of the three main processes that make up the global water cycle is precipitation, along with evaporation and condensation.

Water vapor in the clouds condenses into increasing-sized droplets of water, forming precipitation. Droplets fall to the Earth when they are sufficiently heavy. The water droplets may freeze to produce ice if a cloud is colder, as it would be at higher elevations. Depending on the temperature within the cloud and at the Earth's surface, these ice crystals eventually discharge to the Earth as snow, hail, or rain.

To learn more about precipitation visit:

brainly.com/question/18109776

#SPJ4

6 0
1 year ago
How many gallons of gasoline that is 5% ethanol must be added to 2,000 gallons of gasoline with no ethanol to get a mixture that
Amanda [17]

Answer:

V_1= 3000 gal

Explanation:

We have 3 solutions:

  • Solution 1 (with ethanol)
  • Solution 2 (no ethanol)
  • Final solution

V_f=V_1 + V_2

and for the ethanol:

V_f*0.03=V_1*0.05 + V_2*0

V_f=V_1 \frac{5}{3}

Combining:

V_1 \frac{5}{3}=V_1 + V_2

V_1 \frac{2}{3}= V_2

V_1= \frac{3}{2} V_2

If V2=2000 gal:

V_1= \frac{3}{2} 2000 gal

V_1= 3000 gal

8 0
3 years ago
An undergraduate weighed out 20grams of sodium hydroxide pellets. If Na =23, O = 16 andH = 1, What is the mole of this sodium hy
tatuchka [14]
The answer would be .5 mols because you take the total amount of grams, which is 20, and you had up the molar mass of sodium hydroxide, which would be 40. After you have this you would set this up as a stochiometry equation. With 1 mol on top you dived 20/40 to cancel out your grams. This leaves you with .5 mols

3 0
3 years ago
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