The question here is solved using basic chemistry. CaCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of CaCl2 that dissolves.
CaCl2(s) --> Ca+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.65 mol CaCl2/1L × 2 mol Cl⁻ / 1 mol CaCl2 = 1.3 M
The answer to this question is [Cl⁻] = 1.3 M
Answer:
C
Explanation:
2 N on left so we put a 2 on the right which makes 6 H so we need 6H on the left to do that we add a coef. of 3 to make 6 H and balance the equation
Answer: Hydrochloric acid poses a various health risk
Answer:
The Prandlt number for this fluid is 1630.
Explanation:
The Prandlt number is defined as:

To compute the Prandlt number for this case, is best if we use the same units in every term of the formula.

Now that we have coherent units, we can calculate Pr
