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yaroslaw [1]
3 years ago
12

How would you describe a fossil that was discovered in a rock at the base of a cliff to a fossil in a rock found at the top of a

cliff?
Physics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0
The one at the base would be much older due to the law of super position, and the rock at the top would be much newer,again, due to the law of super position.
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Is a pair of sneakers a want or a need? Is the most expensive pair of sneakers a want or a need?
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Explanation: A sneaker is a want because you don't actually need it to survive

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1. Her angular speed increases because by pulling in her arms she creates a net torque in the direction of rotation. 2. Her angu
choli [55]

Answer:

3. Her angular speed increases because her angular momentum is the same but her moment of inertia decreases

Explanation:

II ωi the intial angular momentum of the skater. Her angular momentum changes to If ωf after pulling her arms in.

It must be noted that If is less than II, then it is because her arms now go round not far from the rotation axis which brings down the mementos of inertia.

Angular momentum does not change since torque is O.

Note: the mathematical representations are better written on the attached diagram.

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which wave behavior results from two waves colliding and the temporary combined wave reaults in a smaller wave than the original
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A 1.2kg stone is tied to a string and swung in a vertical circle with a radius of 0.75m. The string can withstand a tension of 4
san4es73 [151]

Hello!

We can begin by summing the forces acting on the stone when it is at the bottom of its trajectory.

Refer to the free-body diagram in the image below for clarification.

We have the force of tension (produced by the string) and the force of gravity acting in opposite directions, so:
\Sigma F = T - F_g

The net force is equivalent to the centripetal force experienced by the stone. Recall the equation for centripetal force for uniform circular motion:
F_c = \frac{mv^2}{r}

m = mass of object (1.2 kg)
v = velocity of object (? m/s)
r = radius of circle (0.75 m)

The centripetal force is the resultant of the forces of tension and gravity, and points upward (same direction as the tension force) since the tension force is greater.

Therefore:
\frac{mv^2}{r} = T - Mg

We can solve the equation for 'v':

mv^2 = r(T - Mg) \\\\v^2 = \frac{r(T - Mg)}{m}\\\\v = \sqrt{\frac{r(T - Mg)}{m}}

Plug in values and solve.

v = \sqrt{\frac{(0.75)(40 - 1.2(9.8))}{1.2}} = \boxed{4.201 \frac{m}{s}}

3 0
2 years ago
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