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garik1379 [7]
3 years ago
14

What describes how the spring constant affects the potential energy of an object for a given displacement from an equilibrium po

sition?
Physics
1 answer:
Anit [1.1K]3 years ago
8 0

Answer:

The higher the spring constant, the greater the elastic potential energy.

You might be interested in
This problem, a squid at rest suddenly sees a predator coming toward it and needs to escape. Assume the following:______.
makkiz [27]

Answer:

6.79 m/s

Explanation:

By applying the principle of conservation of momentum.

The total momentum = MV - mv = 0 (since the squid is beginning at rest)

the mass of the squid (M) in absence of water in its cavity = (6.5 - 1.75) kg

= 4.75 kg

speed of the squid (V) = 2.5 m/s

mass of the water expelled (m) = 1.75 kg

speed of the water (v) = ???

∴

4.75 × 2.5 = 1.75 × v

v = \dfrac{4.75 \times 2.5}{1.75 }

v = 6.79 m/s

8 0
3 years ago
Which statement does NOT refer to radiation?
fiasKO [112]

B. Warm air rises and takes heat with it; eventually it cools and sinks.

Explanation:

Warm air rising and taking heat with it which eventually cools and sinks describes a typical convection current. This is not radiation

Convection and radiation are both forms of heat transfer alongside conduction.

Radiation is the only form of heat transfer that does not involve the use of a medium or particles.

Air is a medium and it flouts the concept of heat transfer by radiation.

Convection is mostly taking place in fluids especially liquid and gas.

learn more:

Convection brainly.com/question/377220?source=aid8168908

#learnwithBrainly

8 0
4 years ago
Read 2 more answers
How does the orbital velocity of the earth compare to the of mercury?
zalisa [80]

After my ythorough researching, the orbital velocity of the Earth compare to the Mercury is relative to each other. In addition, Mercury orbits the Sun and it is within the Earth's orbit as its lesser or inferior. The correct answer to the following given statement above is relative to each other.

 

8 0
3 years ago
A horizontal beam of electrons initially moving at 4.0×10^7 m/s is deflected vertically by the vertical electric field between o
givi [52]

Answer:

1.77\times 10^{-7}\ C/m^2

0.000439077936334 m

Explanation:

q = Charge of electron = 1.6\times 10^{-19}\ C

E = Electric field = 2\times 10^{4}\ N/C

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

d = Distance between plates = 2 cm (assumed)

m = Mass of electron = 9.11\times 10^{-31}\ kg

The beam consists of electrons which means it has negative charge this means the upper plates will be positive and the lower plate will be negative.

The direction is upper to lower lower plate.

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

Electric flux is given by

\phi=\epsilon_0E\\\Rightarrow \phi=8.85\times 10^{-12}\times 2\times 10^{4}\\\Rightarrow \phi=1.77\times 10^{-7}\ C/m^2

The charge per unit area on the plates is 1.77\times 10^{-7}\ C/m^2

Deflection is given by

s=\dfrac{1}{2}\dfrac{qE}{m}(\dfrac{d}{v})^2\\\Rightarrow s=\dfrac{1}{2}\dfrac{1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}(\dfrac{0.02}{4\times 10^7})^2\\\Rightarrow s=0.000439077936334\ m

The deflection is 0.000439077936334 m

7 0
3 years ago
A physics book slides off a table at 1.25ms and hits the ground after 0.4s
tresset_1 [31]

Answer:

Whats the question here?

7 0
3 years ago
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