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denpristay [2]
4 years ago
8

The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure

Chemistry
1 answer:
Evgen [1.6K]4 years ago
4 0

Answer:

It increases by a factor of four.

Explanation:

To answer this question, we can use the pressure's law, which states that:

"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to the absolute temperature of the gas"

Mathematically:

\frac{p}{T}=const.

where

p is the pressure of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{p_1}{T_1}=\frac{p_2}{T_2}

In this problem we have:

T_2=4T_1, since the absolute temperature of the gas is increased by 4 times

Here we want to find p2; solving for it, we find:

p_2=\frac{T_2}{T_1}p_1 = \frac{4T_1}{T_1}p_1 = 4p_1

So, the pressure

It increases by a factor of four.

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copper hydroxide and potassium sulfate are produced when potassium hydroxide reacts with copper sulfate balanced equation
a_sh-v [17]

This problem is requiring the balanced chemical equation that takes place when copper hydroxide and potassium sulfate are produced when reacting potassium hydroxide with copper sulfate.

<h3>Balancing chemical equations:</h3>

In chemistry, balancing chemical equations is based on the law of conservation of mass, which demands us to have equal number of atoms on both sides of the chemical equation. This can be accomplished by inserting coefficients in front of the chemical species.

For this particular case, we have potassium hydroxide with copper sulfate on the reactants side, however, copper can be copper (I) or copper (II) as it has 1+ and 2+ as its possible oxidation numbers. In addition, copper hydroxide and potassium sulfate as the products. Hence, we can assume this is all about copper (II) so we can write:

KOH+CuSO_4\rightarrow K_2SO_4+Cu(OH)_2

As we can see, potassium, hydrogen and oxygen have two atoms each on the products side, but just one on the reactants side; drawback we can overcome by putting a 2 in front of KOH so as to balance it:

2KOH+CuSO_4\rightarrow K_2SO_4+Cu(OH)_2

Learn more about balancing chemical equations: brainly.com/question/8062886

8 0
3 years ago
The boiling point of water is 100.0°C at 1 atmosphere. How many grams of sodium acetate (82.04 g/mol), must be dissolved in 283.
Alecsey [184]

Answer:

I have to weight 10,04 g of acetate sodium

Explanation:

This is the colligative propertie about elevation of boiling point

ΔT = Kb . m . i  

ΔT is the difference between T° at boiling point of the solution - T° at boiling point of the solvent pure  - we have this data 0,450°C

Kb means ebulloscopic constant (0,52 °C.kg/m .- a known value for water)

m means molality (moles of solute in 1kg of solvent)

i means theVan 't Hoff factor (degree of dissociation for a compound)

For the sodium acetate is 2

NaCH3COO ---> Na+  + CH3COO-

0,450°C = 0,52°C.kg/m . m . 2

0,450°C / (0,52°C.kg/m . 2) = m

0,432 m/kg = m

This number means I have 0,432 moles of acetate sodium, my solute in 1kg of water, my solvent. But I don't have 1000 g (1kg) I only have 283 g so let's make the rule of three:

1000 g _____ 0,432 moles

283 g ______ (283g .0,432m) / 1000g = 0,122 moles

Now that I have the moles of acetate sodium, I have to find the mass.

Moles . molar mass = mass

0,122 moles . 82.04 g/mol = 10,04 g

3 0
4 years ago
Read 2 more answers
What is the meaning of uniformitarianism?
scZoUnD [109]
It's mean the theory that changes in the earth's crust during geological history have resulted from the action of continuous and uniform processes.
7 0
3 years ago
When 20 milliliters of 1.0m hcl is diluted to a total volume of 60 milliliters, the concentration of the resulting solution is?
Ksenya-84 [330]
In preparing diluted solutions from concentrated solutions we can use the following formula
c1v1 = c2v2
c1 and v1 are the concentration and volume of the concentrated solution respectively
c2 and v2 are the concentrations and volume of the diluted solution respectively
Substituting these values ,
20 mL x 1.0 M = C x 60 mL
C = 0.33 M
The concentration of the resulting diluted solutions is 0.33 M
5 0
3 years ago
The density of aluminum is 2.70 g/mL. If you use 108 g of aluminum foil, what is its volume in mL?
Natali5045456 [20]

Answer:

volume =40.0 ml

Explanation:

density = mass/ volume

volume = mass/ density

volume = 108/ 2.70

volume =40.0 ml

3 0
3 years ago
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