A weight suspended from a spring is seen to bob up and down over a distance of 39 cm twice each second. what is its frequency? a
1 answer:
You might be interested in
Answer:
7revolutions
Explanation:
Given parameters:
Initial revolution = 250rpm
Final revolution = 150rpm
Time = 4.2s
Unknown:
Number of revolutions that occur at this time = ?
Solution:
To solve this problem;
let us find the change in revolution = 250rpm - 150rpm = 100rpm
Convert the time to seconds;
60s makes 1 minute
4.2s will make = 0.07min
So;
The number of revolutions at this time = 100rpm x 0.07min
= 7revolutions