Answer:
![\omega_O = 0.16 rad /sec](https://tex.z-dn.net/?f=%5Comega_O%20%3D%200.16%20rad%20%2Fsec)
Q = 0.24
Explanation:
given data:
resonant angular frequency is given as \omega_O = \frac{1}{\sqrt{LC}}
where L is inductor = 150 mH
C is capacitor = 0.25\mu F
![\omega = \frac{1}{\sqrt{150*10^{6}*0.25*10^{-6}}}}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B150%2A10%5E%7B6%7D%2A0.25%2A10%5E%7B-6%7D%7D%7D%7D)
![\omega_O = 0.16 rad /sec](https://tex.z-dn.net/?f=%5Comega_O%20%3D%200.16%20rad%20%2Fsec)
QUALITY FACTOR is given as
![Q = \frac{1}{R}{\sqrt\frac{L}{C}}](https://tex.z-dn.net/?f=Q%20%3D%20%5Cfrac%7B1%7D%7BR%7D%7B%5Csqrt%5Cfrac%7BL%7D%7BC%7D%7D)
Putting all value to get quality factor value
Q =![\frac{1}{1000}{\sqrt\frac{150*10^{6}}{0.25*10^{-6}}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1000%7D%7B%5Csqrt%5Cfrac%7B150%2A10%5E%7B6%7D%7D%7B0.25%2A10%5E%7B-6%7D%7D%7D)
Q = 0.24
We can base this on the equation of thermal expansion.
ΔL = L₀αΔT
where
ΔL is the expansion of length upon heating
L₀ is the initial length
α is the coefficient of linear expansion
ΔT is the temperature difference
So, if α for Aluminum is greater than α for Copper, then after heating, aluminum would be longer than copper.
It is how forces affect nature