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Leona [35]
3 years ago
5

In which wavelength region(s) would we need to carry out observations in order to study the accretion disk around a white dwarf

in a binary system?
Physics
1 answer:
Inga [223]3 years ago
7 0

In “Ultraviolet light” and “X-ray” light wavelength regions are needed to carry out observations to study the “accretion disk” around “a white dwarf” in a “binary system”.

<u>Explanation</u>:

Occurrence of an accretion disk is due to presence of diffuse material around a white dwarf in orbital motion. White dwarf is constituted from electron-degenerate matter therefore also called as degenerate dwarf in binary system. Frictional forces and gravitational forces are responsible to compress and high “temperature” of the material, results with emission of “electromagnetic radiation”. “Accretion disks” of white dwarf radiate in the UV-rays and X-rays wavelength region of spectrum.

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Calculate kp at 298.15 k for the reactions (a), (b), and (c) using δg°f values.
vivado [14]
(a) 2NO(g) + O₂(g) ⇄2NO₂(g)kp
(b)  2N₂O(g)⇄2NO(g) + N₂(g) kp
(c)  N₂(g) + O₂(g)⇄ 2NO(g) kp
Now A is
2NO +O₂⇄2NO₂
ΔG° =ΔG° products - ΔG reactants
=2× 51.3-(256.6)
-70.6kJ/mol.
ΔG° = -RT Inkp
-70.6 = -8.314 ×10⁻³ ˣ 298.15 ˣInkJ
InkJ = 28.48
kp=2.34 ˣ 10¹²

B is 
ΔG° = 2× 86.6 - 2 × 104.2 = -35.2
-35.2 = 8.314 × 10⁻³ ˣ 298.15 ˣInkJ
InkJ = 14.2
kp = 1.47ˣ 10⁶

C is
It is also similar
kp = 4.62 ˣ 10⁻³I
6 0
3 years ago
If you know the distance an object has traveled in a certain amount of time you can determine
Nutka1998 [239]
With that information, you can determine the object's speed.
Just divide the distance covered by the time to cover the distance.

If you also know the direction the object moved, then you can
determine its velocity.  If you don't, then you can't.
5 0
3 years ago
Read 2 more answers
A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou
Whitepunk [10]

Total distance = 36500 m

The average velocity = 19.73 m/s

<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

a=acceleration= 1 m/s²

t₁ = 20 s

t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m

\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s

State 2 : constant speed

\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m

State 3 : deceleration

\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)

\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m

Total distance : state 1+ state 2+state 3

\tt 200 + 36000 + 300=36500~m

the average velocity = total distance : total time

\tt avg~velocity=\dfrac{36500}{20~s+1800~s+30~s}=19.73~m/s

4 0
2 years ago
Scientists use what scale to compare the hardness of minerals?
frozen [14]
Mohs hardness scale. hope this helps
4 0
2 years ago
After the box comes to rest at position x1, a person starts pushing the box, giving it a speed v1. when the box reaches position
KiRa [710]

As we know by work energy theorem

total work done = change in kinetic energy

so here we can say that wok done on the box will be equal to the change in kinetic energy of the system

W_p = KE_f - KE_i

initial the box is at rest at position x = x1

so initial kinetic energy will be ZERO

at final position x = x2 final kinetic energy is given as

KE_f = \frac{1}{2}mv_1^2

now work done is given as

W_p = \frac{1}{2}mv_1^2 - 0

so we can say

W_p = \frac{1}{2}mv_1^2

so above is the work done on the box to slide it from x1 to x2

3 0
3 years ago
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