M=n(pie)/RT
n=osmotic pressure(1.2 atm)
M=molar of the solution
R=gas constant(0.0821)
T= temperature in kelvin 25+273
M=[1.2atm /(0.0821L atm/k mol x 298k)]=0.049mol L
M= moles of the solute/ litres of solution(250/1000)
0.049= y/0.25
moles of solute is therefore =0.01225mol
molar mass=33.29 g/0.01225mol=2.7 x10^3g/mol
It is important to determine the qcalorimeter before determining the qmetal because the qcalorimeter is a constant and it's value is used to find the value of qmetal.
Answer:
Explanation:
The expression for the calculation of the enthalpy change of a process is shown below as:-
Where,
is the enthalpy change
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass of ammonium nitrate = 1.25 g
Specific heat = 4.18 J/g°C
So,
Negative sign signifies loss of heat.
Also, 1 J = 0.001 kJ
So,