The answer is Al which is option B
Answer: 404.04 kJ.
Explanation:
To calculate the moles, we use the equation:
moles of
According to stoichiometry :
2 moles of on burning produces = 1036 kJ
Thus 0.78 moles of on burning produces =
Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.
True!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Equation is as follow,
<span> SnCl</span>₂ <span> + PbCl</span>₄<span> </span>→ <span>SnCl</span>₄ <span> + PbCl</span>₂
Oxidation State of Sn on left hand side in SnCl₂ is +2, while that in SnCl₄ on right hand side is +4. Means Sn has lost two electrons. Hence, it is oxidized and has worked as a reducing agent (has reduced Pb from Pb⁺⁴ to Pb⁺²).
Oxidation State of Pb on left hand side in PbCl₄ is +4, while that in PbCl₂ on right hand side is +2. Means Pb has gained two electrons. Hence, it is reduced and has worked as an oxidizing agent (has oxidized Sn from Sn⁺² to Sn⁺⁴).