Magnetic field lines appear _____.
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The given compound 1,2-dibromo-2-methylbutane is an optically active compound .
Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .
It has chiral center.
Here , the chiral carbon is attached to the 4 distinct groups such as : methyl , ethyl , bromine , bromomethane .
<h3>What is di-symmetry?</h3>Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .
<h3>Chiral center :</h3>Have Sp3 hybridized center (4sigma bond ) .
4 distinct group is attached to the chiral atom. form non -superimposable mirror image .
<h3>What is optical isomerism ?</h3>Same molecular formula and same structural formula . also have same physical and chemical properties .
They differ in their behavior towards plane polarized light (ppl) .
Learn more about chiral center here:
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According to Hasselbach-Henderson equation:
Here, is concentration of conjugate base and [HA] is concentration of acid.
In the given problem, conjugate base is and acid is
thus, Hasselbach-Henderson equation will be as follows:
...... (1)
(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,
Also,
Putting the values in equation (1),
Therefore, pH of solution is 5.06.
(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,
Also,
Putting the values in equation (1),
Therefore, pH of solution is 4.28.
(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,
Also,
Putting the values in equation (1),
Therefore, pH of solution is 5.45.
(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,
Also,
Putting the values in equation (1),
Therefore, pH of solution is 4.76.
(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,
Also,
Putting the values in equation (1),
Therefore, pH of solution is 3.76.