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lutik1710 [3]
3 years ago
7

In this problem, you will analyze a system composed of two blocks, 1 and 2, of respective masses m1 and m2. To simplify the anal

ysis, we will make several assumptions:
The blocks can move in only one dimension, namely, along the x axis.
The masses of the blocks remain constant.
The system is closed.
At time t, the x components of the velocity and the acceleration of block 1 are denoted by v1(t) and a1(t). Similarly, the x components of the velocity and acceleration of block 2 are denoted by v2(t)and a2(t).
1. Let us denote the force exerted by block 1 on block 2 by F12, and the force exerted by block 2 on block 1 by F21. If we suppose that m1 is greater than m2, which of the following statements about forces is true?
a. |F12|>|F21|
b. |F21|>|F12|
c. Both forces have equal magnitudes.
Physics
1 answer:
storchak [24]3 years ago
7 0

Answer:

c. Both forces have equal magnitudes.

Explanation:

According to Newton´s 3rd Law, the force exerted by a body on another one , is equal and opposite to the one that the second object exerts on the first one.

This does not depend on the masses of the objects, so it doesn´t matter that m₁ be greater than m₂.

As examples of this, we can mention the gravity force, the electrostatic force, the normal force, etc.

So, in this case, taking into account only the magnitudes, we can say:

F₁₂ = F₂₁

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A kangaroo jumps straight up to a vertical height of 1.45 m. How long was it in the air before returning to Earth?
dexar [7]

Answer:

1.08 s

Explanation:

From the question given above, the following data were obtained:

Height (h) reached = 1.45 m

Time of flight (T) =?

Next, we shall determine the time taken for the kangaroo to return from the height of 1.45 m. This can be obtained as follow:

Height (h) = 1.45 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

1.45 = ½ × 9.8 × t²

1.45 = 4.9 × t²

Divide both side by 4.9

t² = 1.45/4.9

Take the square root of both side

t = √(1.45/4.9)

t = 0.54 s

Note: the time taken to fall from the height(1.45m) is the same as the time taken for the kangaroo to get to the height(1.45 m).

Finally, we shall determine the total time spent by the kangaroo before returning to the earth. This can be obtained as follow:

Time (t) taken to reach the height = 0.54 s

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T = 2t

T = 2 × 0.54

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Therefore, it will take the kangaroo 1.08 s to return to the earth.

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A ball falls off of a 3m tall shelf. How long will it take for the
natali 33 [55]

Answer:

0.8s

Explanation:

Given parameters:

Height of shelf  = 3m

Unknown:

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