A plane is flying due east with the velocity of 90m/s. The wind is blowing out of the north at 4m/s. What is the magnitude of th
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Explanation:
We need convert the velocities first to m/s and we get the following:
v2 = 21 km/hr = 5.8 m/s
v1 = 11 km/hr = 3.1 m/s
We need to find the mass of the car also for later use do using the work-energy theorem:
6.0x10^3 J = (0.5) m [(5.8)^2 - (3.1)^2]
or
m = 499.4 kg
Now we determine work needed delta W to change its velocity from 21 km/hr to 33 km/hr
v2 = 33 km/hr = 9.2 m/s
v1 = 21 km/hr = 5.8 m/s
delta W = (0.5)(499.4)[(9.2)^2 - (5.8)^2]
= 1.3 x 10^4 J
Work done can be computed using the formula:
Where:
W = work (J)
F = Force (N)
d = Distance (d)
Looking at the given, you know that you do not have a value for force, so you will have to solve for it.
Where:
F = Force
m = mass
a = acceleration
Because the object is being lifted, the acceleration will rely on gravity. Acceleration due to gravity is a constant 9.8 m/s^2. Let's list our given first:
F = ?
m = 100kg
a = 9.8m/s^2
Put that into our equation and solve:
Our force is then 980 N.
Now that we have force we can solve for Work. The given for work is as follows:
F= 980N
d = 1.4m
Put that into our formula and solve:
The work done is 1,372J.
Where:
W = work (J)
F = Force (N)
d = Distance (d)
Looking at the given, you know that you do not have a value for force, so you will have to solve for it.
Where:
F = Force
m = mass
a = acceleration
Because the object is being lifted, the acceleration will rely on gravity. Acceleration due to gravity is a constant 9.8 m/s^2. Let's list our given first:
F = ?
m = 100kg
a = 9.8m/s^2
Put that into our equation and solve:
Our force is then 980 N.
Now that we have force we can solve for Work. The given for work is as follows:
F= 980N
d = 1.4m
Put that into our formula and solve:
The work done is 1,372J.