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3 years ago

Classify the following sets of measurements as accurate, precise, both, or neither.

Chemistry

1 answer:

azamat3 years ago

3 0

Answer:

Explanation:

Accuracy is defined is as the ability to perfectly repeat results in an experiment. It is simply reproducing the same set of result with little to no altercation.

Precision is nearness of the result to the true value.

(a) Checking for consistency in the weight of chocolate chip cookies: 17.27 g, 13.05 g, 19.46 g, 16.92 g

The result above is neither accurate nor precise. We can see a lot of inconsistencies in the readings shown and no repeatability whatsoever.

(b) Testing the volume of a batch of 25- mL pipettes: 27.02mL, 26.99 mL, 26.97 mL, 27.01 mL

The results here are accurate but not precise. They are a little bit off the 25mL mark but the experiment was able to reproduce nearly the same result.

(c)Determining the purity of gold: 99.9999%, 99.9998%, 99.9999%

This result is both precise and accurate. Pure Gold should be 100% and our values are very close. The experiment also was able to generate very accurate results.

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The mass of proton<br>1) 1072* 10-28

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Answer:

Mass of proton is

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3 years ago

Reaction rate is increased by an increase in kinetic energy

marta [7]

Answer:

Reaction rate is increased by an increase in kinetic energy

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is _temperature_

increased

A . Collision theory

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1 year ago

How does carbonation affect melting point

FromTheMoon [43]

The sodium in soda lowers the melting point and makes the ice melt more slowly than it would in plain water because with the addition of any substance, there are fewer free water molecules available to form bonds together and freeze

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10 months ago

Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti

gayaneshka [121]

Answer : The value of $K$ for this reaction is, $2.6\times 10^{15}$

Explanation :

The given chemical reaction is:

$CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)$

Now we have to calculate value of $(\Delta G^o)$ .

$\Delta G^o=G_f_{product}-G_f_{reactant}$

$\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]$

where,

$\Delta G^o$ = Gibbs free energy of reaction = ?

n = number of moles

$\Delta G^0_{(HCH_3CO_2(g))}$ = -389.8 kJ/mol

$\Delta G^0_{(CH_3OH(g))}$ = -161.96 kJ/mol

$\Delta G^0_{(CO(g))}$ = -137.2 kJ/mol

Now put all the given values in this expression, we get:

$\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]$

$\Delta G^o=-89.4kJ/mol$

The relation between the equilibrium constant and standard Gibbs, free energy is:

$\Delta G^o=-RT\times \ln K$

where,

$\Delta G^o$ = standard Gibbs, free energy = -89.4 kJ/mol = -89400 J/mol

R = gas constant = 8.314 J/L.atm

T = temperature = $30.0^oC=273+30.0=303K$

$K$ = equilibrium constant = ?

Now put all the given values in this expression, we get:

$-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K$

$K=2.6\times 10^{15}$

Thus, the value of $K$ for this reaction is, $2.6\times 10^{15}$

4 0

3 years ago

Solid-solid homogeneous mixture give one example

likoan [24]

Example of solid - solid homogeneous mixture is copper metal - silver metal like coins and alloys. Homogeneous mixture is a mixture in which one of the substances often changes in form as in a solution of sugar in water. It contains variable proportions. Solution can contain two substances, three substances or more, in a single physical state. The component of a solution that is present in greatest quantity is usually called the solvent and all other components are called solutes.

5 0

3 years ago

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